TensorFlow-类似于numpy的张量索引

Question

In numpy, we can do this:

x = np.random.random((10,10))
a = np.random.randint(0,10,5)
b = np.random.randint(0,10,5)
x[a,b] # gives 5 entries from x, indexed according to the corresponding entries in a and b

When I try something equivalent in TensorFlow:

xt = tf.constant(x)
at = tf.constant(a)
bt = tf.constant(b)
xt[at,bt]

The last line gives a "Bad slice index tensor" exception. It seems TensorFlow doesn't support indexing like numpy or Theano.

Does anybody know if there is a TensorFlow way of doing this (indexing a tensor by arbitrary values). I've seen the tf.nn.embedding part, but I'm not sure they can be used for this and even if they can, it's a huge workaround for something this straightforward.

(Right now, I'm feeding the data from x as an input and doing the indexing in numpy but I hoped to put x inside TensorFlow to get higher efficiency)

Answer 1

You can actually do that now with tf.gather_nd . Let's say you have a matrix m like the following:

| 1 2 3 4 |
| 5 6 7 8 |

And you want to build a matrix r of size, let's say, 3x2, built from elements of m , like this:

| 3 6 |
| 2 7 |
| 5 3 |
| 1 1 |

Each element of r corresponds to a row and column of m , and you can have matrices rows and cols with these indices (zero-based, since we are programming, not doing math!):

       | 0 1 |         | 2 1 |
rows = | 0 1 |  cols = | 1 2 |
       | 1 0 |         | 0 2 |
       | 0 0 |         | 0 0 |

Which you can stack into a 3-dimensional tensor like this:

| | 0 2 | | 1 1 | |
| | 0 1 | | 1 2 | |
| | 1 0 | | 2 0 | |
| | 0 0 | | 0 0 | |

This way, you can get from m to r through rows and cols as follows:

import numpy as np
import tensorflow as tf

m = np.array([[1, 2, 3, 4], [5, 6, 7, 8]])
rows = np.array([[0, 1], [0, 1], [1, 0], [0, 0]])
cols = np.array([[2, 1], [1, 2], [0, 2], [0, 0]])

x = tf.placeholder('float32', (None, None))
idx1 = tf.placeholder('int32', (None, None))
idx2 = tf.placeholder('int32', (None, None))
result = tf.gather_nd(x, tf.stack((idx1, idx2), -1))

with tf.Session() as sess:
    r = sess.run(result, feed_dict={
        x: m,
        idx1: rows,
        idx2: cols,
    })
print(r)

Output:

[[ 3.  6.]
 [ 2.  7.]
 [ 5.  3.]
 [ 1.  1.]]

Answer 2

LDGN's comment is correct. This is not possible at the moment, and is a requested feature. If you follow issue#206 on github you'll get updated if/when this is available. Many people would like this feature.

Answer 3

For Tensorflow 0.11 , basic indexing has been implemented. More advanced indexing (like boolean indexing) is still missing but apparently is planned for future versions.

Advanced indexing can be tracked with https://github.com/tensorflow/tensorflow/issues/4638