如何遍历循环并打印循环值

Question

I have the following Array:

   Nod= ['338', '299', '299', '300', '300', '335', '336', '314', '335', '336', '337', '338', '309', '337', '314', '309']

Now i have to write a code such that it Loops through Nod[] and assign certain variables to first two numbers, like the folowing:

1. Node1 = 338
2. Node2= 299
3. Search for Node2(ie 299) in the remaing sets
4. And assign the adjacent value to Node3 ie Node3= 300
5. Detele all the numbers which are used
6. Loop ends here and from the next loop it should search for Node3 value and assign it as Node1

Continue the loop untill Nod= = 0

and the result of the code should look like

First loop

Node1= 338
Node2= 299
Node3= 300

In Second loop

Node1= 300
Node2=335
Node3=336

In Third loop

Node1=336
Node2=314
Node3=309

4th

Node1=309
Node2=337
Node3=338

and Loop Ends here

I am very new to coding and python, pls help me with writing the code. I have tried with different Loops but couldnt be able to figure out the logic and code. Thanks in advance.

Answer 1

node= ['338', '299', '299', '300', '300', '335', '336', '314', '335', '336', '337', '338', '309', '337', '314', '309']
while(len(node)!=3):
    fst_element = node[0]
    snd_element = node[1]
    third_element = node[2:][node[2:].index(snd_element)+1]
    print "fst: %s\t2nd: %s\t3rd: %s"%(fst_element,snd_element,third_element)
    node = [x for x in node[2:] if x != fst_element]
    node = [x for x in node if x != snd_element]
    node = [x for x in node if x != third_element]
    node.insert(0,third_element)
print "last result: " + str(node) 

The above is what you want, I suppose. I think the result of the last iteration is:

Node1=309
Node2=337
Node3=337 

According to your algorithm the number 338 was already removed from the first iteration.

Happy learning python.