[英]How can I crop an image properly with php?
I am trying to crop an image on PHP
. 我正在尝试在
PHP
上裁剪图像。 I saw that there is a function for doing that on PHP
: imagecrop . 我看到有一个在
PHP
上执行此操作的函数: imagecrop 。 Here is the code in which I am trying to crop the image. 这是我尝试裁剪图像的代码。
$image = imagecreatefromjpeg(//Path of the image);
$croppedImage = imagecrop($image, array("x"=>0,"y"=>0,"width"=>100,"height"=>100));
imagejpeg($croppedImage, //Path in which the image will be stored);
Here I want that the crop of the image starts in the left corner of the image and get the values of width and height that I put above. 在这里,我希望图像的裁剪从图像的左角开始,并获得我在上方放置的width和height的值。
But it just resize my image, not crop it. 但这只是调整我的图像大小,而不是裁剪图像。 What am I doing wrong?
我究竟做错了什么?
EDIT: 编辑:
I tried also with the function imagecopyresampled . 我也尝试了imagecopyresampled函数。 Here it is what I have tried:
这是我尝试过的:
dst_image(Destination image link resource) = newImage; //Here the new image that I want to create.
src_image(Source image link resource) = image; //Here the original image.
//Here 0,0 because I want that the new image crop starts in the left corner of the original image.
dst_x(x-coordinate of destination point) = 0;
dst_y(y-coordinate of destination point) = 0;
//Here 0,0 because I want that the crop starts on the 0,0 of the original image
src_x(x-coordinate of source point) = 0;
src_y(y-coordinate of source point) = 0;
dst_w(Destination width) = 150; //The new width of the crop image.
dst_h(Destination height) = 150; //The new height of the crop image.
src_w(Source width) = 500; //The original width of the image.
src_h(Source height) = 500; //The original height of the image.
So finally the function will be like: 因此,最终的功能将类似于:
$b = imagecopyresampled ($dst_image, $src_image, $dst_x, $dst_y, $src_x, $src_y, $dst_w , $dst_h , $src_w , $src_h );
I just have problems in this function it is why avoid the rest (save and imagetruecolor and the rest...) 我只是在此函数中有问题,这就是为什么要避免其余部分(保存和imagetruecolor以及其余部分...)
This function give to me the result expected but the new image it is black, why? 此功能给我预期的结果,但是新图像为黑色,为什么?
Thanks in advance! 提前致谢!
try this: 尝试这个:
$dst_x = 0; // X-coordinate of destination point
$dst_y = 0; // Y-coordinate of destination point
$src_x = 100; // Crop Start X position in original image
$src_y = 100; // Crop Srart Y position in original image
$dst_w = 160; // Thumb width
$dst_h = 120; // Thumb height
$src_w = 260; // $src_x + $dst_w Crop end X position in original image
$src_h = 220; // $src_y + $dst_h Crop end Y position in original image
// Creating an image with true colors having thumb dimensions (to merge with the original image)
$dst_image = imagecreatetruecolor($dst_w, $dst_h);
// Get original image
$src_image = imagecreatefromjpeg('images/cropped_whatever.jpg');
// Cropping
imagecopyresampled($dst_image, $src_image, $dst_x, $dst_y, $src_x, $src_y, $dst_w, $dst_h, $src_w, $src_h);
// Saving
imagejpeg($dst_image, 'images/crop.jpg');
另外,您可以使用的功能imagecrop imagick 。
Finally, I got the solution of my problem. 最后,我找到了解决问题的方法。 I had to put the same value of
dst_w
and src_w
. 我必须输入相同的
dst_w
和src_w
值。 The same to dst_h
and src_h
. 与
dst_h
和src_h
相同。 ¡¡And it works!! ¡¡
The final solution it is the following: 最终的解决方案如下:
$b = imagecopyresampled ($dst_image, $src_image, 0, 0, 0, 0, 150, 150, 150, 150);
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