从列表中删除方括号和双引号

Question

I need to remove Square brackets and Double quotes from python list for further processing of data.

My code for the same is as follows:

ips = ['1.2.3.5','1.2.3.4']
y = []

for ip in ips:
        x = "model.data.like('%"+ip+"%'),"
        y.append([x])
print y

So here final result which I got is as follows:

["model.data.like('%1.2.3.5%'),"], ["model.data.like('%1.2.3.4%'),"]

Now here I need to get rid of square brackets and double quotes.

I need the output as follows:

model.data.like('%1.2.3.5%'),model.data.like('%1.2.3.4%')

Please have a note that IP address is dynamic one, List can contain more than two IP addresses.

Answer 1

Use flattening list and join function-

>>>t=[item for sublist in y for item in sublist]
>>print t
>>>["model.data.like('%1.2.3.5%'),", "model.data.like('%1.2.3.4%'),"]
>>>data =  ''.join(t)
>>>print data
>>>model.data.like('%1.2.3.5%'),model.data.like('%1.2.3.4%'),
>>>cleaned_data = data.rstrip(',')
>>>print cleaned_data
>>>model.data.like('%1.2.3.5%'),model.data.like('%1.2.3.4%')

Answer 2

You can use formatting the string by accessing the element of list .

In [58]: s = ''

In [59]: for i in ips:
    s = s + "model.data.like (%{}%),".format(i)

In [72]: s[:-1]
Out[72]: 'model.data.like (%1.2.3.5%),model.data.like (%1.2.3.4%)'

Answer 3

So, you do want to make a string from list? That's simple, you can use str.join to do this:

ips = ['1.2.3.5','1.2.3.4']

# this is list comprehension, it does the same thing as your loop
y = ["model.data.like('%"+ip+"%')" for ip in ips]

print  ','.join(y)