Nginx配置两个PHP版本

Question

I'm trying to set up an nginx environment where legacy code and new MVC-style code can co-exist, so that I can gradually refactor it page by page. The legacy code needs an older version of PHP (it runs best on 5.3, but I had trouble compiling that, so I went with 5.4 and will fix anything that breaks), but it is easily distinguishable by URL, because it has literal file names like http://sub.domain.com/search.php?category=4 , etc. instead of new style like http://sub.domain.com/search/category/4 - the key difference is the presence of .php .

The new code runs fine with the following in the nginx config:

server {
  listen 80;
  server_name *.myproject.dev;
  root /var/www/myproject/public;
  index index.php index.html index.htm;
  try_files $uri $uri/ @rewrite;
  location @rewrite {
    rewrite ^/(.*)$ /index.php?_url=/$1;
  }
  location ~ ^(.+\.php)(/.*)?$ {
    fastcgi_param PATH_INFO $fastcgi_path_info;
    fastcgi_param PATH_TRANSLATED $document_root$fastcgi_path_info;
    fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
    fastcgi_pass unix:/var/run/php5-fpm.sock;
    fastcgi_split_path_info ^(.+\.php)(/.+)$;
    include fastcgi_params;
  }
}

(I will admit that I don't completely understand all that code - it came from various guides and such.)

With the help of this great tutorial I compiled and installed PHP 5.4 in its own location listening on port 9001. It works fine using a separate domain for the old code, but what I want to do is use a single domain, but call the old code if .php is found in the URL, and do the requisite rewrite on anything else and use the new code. I found this post on ServerFault and tried incorporating its ideas in my situation like this:

server {
  listen 80;
  server_name *.myproject.dev;
  root /var/www/myproject/public;
  index index.php index.html index.htm;
  try_files $uri $uri/ @rewrite;
  location @rewrite {
    rewrite ^/(.*)$ /index.php?_url=/$1;
  }
  location ~ ^(.+\.php)(/.*)?$ {
    fastcgi_param PATH_INFO $fastcgi_path_info;
    fastcgi_param PATH_TRANSLATED $document_root$fastcgi_path_info;
    fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
    fastcgi_pass unix:/var/run/php5-fpm.sock;
    fastcgi_split_path_info ^(.+\.php)(/.+)$;
    include fastcgi_params;

    # Anything with ".php" is directed to the old codebase
    location ~* \.php {
      root /var/www/myproject/oldcode;
      fastcgi_pass 127.0.0.1:9001;
    }
  }
}

But the rewrite adds index.php to the new code, so in the end, everything matches the .php test, which is not the intent. I tried putting those final four lines earlier in the file with several variations, but that didn't help (either a blank page or still only going to the old code location, depending on the details). Does someone know enough about nginx config syntax to help me rearrange it so that it does what I want?

Answer 1

If your new code only uses /index.php and without any path_info, you could use a prefix location:

location ^~ /index.php { ... }
location ~* \.php { ... }

The first location takes precedence due to the ^~ operator. Or an exact match (which also takes precedence):

location = /index.php { ... }
location ~* \.php { ... }