[英]Find the sum from the results of two SQL queries
declare @CURDATETIME DATETIME
SET @CURDATETIME = GETDATE()
Select
(select COUNT(TABLE1.RECID) AS Expr1
FROM TABLE1 LEFT OUTER JOIN
TABLE2 ON TABLE2.ISSUEID = TABLE1.ISSUEID
WHERE (TABLE1.STATUS = 3) AND (TABLE2.NOTIFICATIONINDEP = 1)) AS OpenNotifications,
(Select
count(TABLE1.RECID) AS [ar3]
from TABLE1 left outer join
TABLE2 ON TABLE2.ISSUEID = TABLE1.ISSUEID
where TABLE1.STATUS = 4
and TABLE2.NOTIFICATIONINDEP = 1
AND dateadd(second, TABLE1.CREATEDTIME, TABLE1.createddate) <= dateadd(hour, -1, @CURDATETIME)
and dateadd(second, TABLE1.FinishedTime, TABLE1.FinishedDate) between dateadd(hour, -2, @CURDATETIME) and @CURDATETIME) as AR3,
(Select
count(TABLE.RECID) as [ar4]
from TABLE1 left outer join
TABLE2 ON TABLE2.ISSUEID = TABLE1.ISSUEID
where TABLE1.STATUS = 3 and TABLE2.NOTIFICATIONINDEP = 1
and dateadd(second, TABLE1.createdtime, TABLE1.createddate) < dateadd(hour, -1, getdate())) as AR4,
Your question is not very clear but as you told in comments, you can sum the count of 2 select statemets like below (assuming your select statements are working and returning integer values) and use this in your query.您的问题不是很清楚,但正如您在评论中所说,您可以对如下所示的 2 个选择语句的计数求和(假设您的选择语句正在工作并返回整数值)并在您的查询中使用它。
select
(Select
count(TABLE1.RECID) AS [ar3]
from TABLE1 left outer join
TABLE2 ON TABLE2.ISSUEID = TABLE1.ISSUEID
where TABLE1.STATUS = 4
and TABLE2.NOTIFICATIONINDEP = 1
AND dateadd(second, TABLE1.CREATEDTIME, TABLE1.createddate) <= dateadd(hour, -1, @CURDATETIME)
and dateadd(second, TABLE1.FinishedTime, TABLE1.FinishedDate) between dateadd(hour, -2, @CURDATETIME) and @CURDATETIME)
+
(Select
count(TABLE.RECID) as [ar4]
from TABLE1 left outer join
TABLE2 ON TABLE2.ISSUEID = TABLE1.ISSUEID
where TABLE1.STATUS = 3 and TABLE2.NOTIFICATIONINDEP = 1
and dateadd(second, TABLE1.createdtime, TABLE1.createddate) < dateadd(hour, -1, getdate()))
as total from dual
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