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父圆角与孩子重叠

[英]Parent rounded corners overlap with child

I am stuck with a problem, I have a nav and in it i got two div and in those I got one li each. 我陷入了一个问题,我有一个nav ,在其中有两个div ,在其中每个都有一个li I want the div s to overlap the nav bar but what is making me stuck is that I want the nav bar to get rounded corners where the div overlaps it means that the div s need to stretch out their corners to make a rounded form for the nav bar. 我希望div重叠nav栏,但是让我陷入困境的是,我希望nav栏在div重叠的地方获得圆角,这意味着div需要伸出自己的角以形成圆形nav栏。 Is that possible and how could I do that? 那有可能吗,我该怎么做?

 ul { list-style: none; } div { display: inline-block; width: 20%; height: 30px; margin: 0; position: relative; text-align: center; -webkit-transform: skew(-40deg); -moz-transform: skew(-40deg); -o-transform: skew(-40deg); background-color: #ddd; } nav { background-color: #777; padding: 0; } li { font-size: 0.8em; position: relative; top: 505; margin-top: -0.4em; -webkit-transform: skew(40deg); -moz-transform: skew(40deg); -o-transform: skew(40deg); } 
 <nav> <ul> <div class="overlapping_div"> <li>Text in div</li> </div> <div class="overlapping_div"> <li>Text in div</li> </div> </ul> </nav> 

li needs to be the direct child of a ul, in order to do what you want maybe try this solution: li需要成为ul的直系子孙,以便执行您想要的操作,也许可以尝试以下解决方案:

<nav>
  <ul>
      <li class="overlapping_div">
          <span>Text in div</span>
      </li>
      <li class="overlapping_div">
          <span>Text in div</span>
      </li>
  </ul>
</nav>

and the CSS looks like this CSS看起来像这样

ul {
  list-style: none;
}

.overlapping_div {
  display: inline-block;
  width: 20%;
  height: 30px;
  margin: 0;
  position: relative;
  text-align: center;
  -webkit-transform: skew(-40deg);
  -moz-transform: skew(-40deg);
  -o-transform: skew(-40deg);
  background-color: #ddd;
}
nav {
  background-color: #777;
  padding: 0;
}
span {
  font-size: 0.8em;
  position: relative;
  top : 5px;
  display : block;
  -webkit-transform: skew(40deg);
  -moz-transform: skew(40deg);
  -o-transform: skew(40deg);
}

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