Linux Shell脚本，用于使用参数调用Java程序

Question

I have a java program that runs as a service in linux box. I have shell script file that has the following line to start the program.

$EXEC -home "$JAVA_HOME" -cp "$CLASS_PATH" -outfile "$LOG_OUT" -errfile "$LOG_ERR" -pidfile "$PID" $1 $CLASS 

$CLASS_PATH has class path
$CLASS has the name of main class
EXEC="/usr/bin/jsvc"

I can start and stop the service using following commands

• service myscriptfilename start

• service myscriptfilename stop

Now I added a new argument to my program called "myflag" . It works fine on windows box . Now I am having difficulty passing the new argument to my program on my linux box using the shell script.

Now I am starting my service as

• service myscriptfilename start myflag

I can get the value of myflag using $2 in shell script. I am trying to figure out how do I pass that to my program

How can i pass my "myflag" to my program from shell script in the following line?

$EXEC -home "$JAVA_HOME" -cp "$CLASS_PATH" -outfile "$LOG_OUT" -errfile "$LOG_ERR" -pidfile "$PID" $1 $CLASS

Answer 1

I am considering that $EXEC is java executable, $1 is your JAR, $CLASS is your main class. In this case just append ${@:2} to the end of the line:

$EXEC -home "$JAVA_HOME" -cp "$CLASS_PATH" -outfile "$LOG_OUT" -errfile "$LOG_ERR" -pidfile "$PID" $1 $CLASS ${@:2}