在函数中传递指针到字符：语法错误

Question

My question is related to my previous post:

explicit specialization: syntax error?

I am trying to pass arrays of pointer-to-chars as an argument to a function (which I will later incorporate to a specialized function from previous post), but I cannot get the syntax right.

The following were declared under main program:

char c0[30] = { "see if this works" };
char c1[30] = { "functions" };
char c2[30] = { "explicit specialization" };
char *d[] = { c0, c1, c2 }; 

the next line prints "functions " as I was expecting:

cout << "test print d[1] " << d[1] << endl;

The next step is to test whether I am able to return the character-array that I want to return, but my syntax is incorrect. The following returns 's' (from c0) instead of an entire char-array:

function call:

cout << "string compare is " << compare2(*d, 3);

function declaration:

char compare2(char const arr2[], int n) {
    char temp;
    temp = arr2[0];

    return temp;

appreciate the help!

Answer 1

Oh never mind. I figured it out :D

pointer declaration:

char *(d[]) = { c0, c1, c2 };

function call:

cout << "string compare is " << compare2(d, 3);

function definition:

char * compare2(char * const arr2[], int n) {
    char * temp;
    temp = *(arr2+2);

    return temp;
}