仅使用 currentTimeMillis() 来获取日期

Question

So I'm totaly lost. I have to print out the actual Date and time using only currentTimeMillis() and nothing else. Getting the time was no problem:

long t = java.lang.System.currentTimeMillis();

long seconds = (t / 1000) % 60;
long minutes = (t / (1000 * 60)) % 60;
long hours = (t / (1000 * 60 * 60) % 24) + zone;

But how can I calculate the date taking leap years into consideration?

Edit: It's homework, hence this weird question. And we are not allowed to use any other methodes besides currentTimeMillis(). Operators and alike are fine.

Answer 1

There is no way to do this without using anything else . You have to be more clear about which restrictions there are and why? Is this homework?

The simplest way I can think of is:

long t = java.lang.System.currentTimeMillis();
System.out.println(new Date(t));

But I am sure that's not what you need. Please elaborate...

Answer 2

For the timezone related problem, following fix can be used. However this is just one case: other cases need to be handled as well.

//let's say time zone is +5:30
long zone = 6; //instead of 5, keeping value 6, thus added extra 30 minutes
long minuten = (t / (1000 * 60)) % 60;
long stunden = (t / (1000 * 60 * 60) % 24) + zone;
if(minuten < 30){ // this is to take care of the cases where hour has moved ahead
    stunden--;
    minuten+=30;
} else{
    minuten-=30; // else deduct those additional 30 minutes
}