[英]Extract string from a Tuple in python with psycopg2
I have written a web.py service in python to access PostGres and get the table names inside the specific database. 我已经在python中编写了一个web.py服务来访问PostGres并获取特定数据库中的表名。
CODE: 码:
def GET(self,r):
web.header('Access-Control-Allow-Origin', '*')
web.header('Access-Control-Allow-Credentials', 'true')
tables = []
datasetID = web.input().dataSetID
cursor = conn.cursor()
cursor.execute("select relname from pg_class where relkind='r' and relname !~ '^(pg_|sql_)';")
tablesWithDetails = cursor.fetchall()
print tablesWithDetails
for x in tablesWithDetails:
x.replace("(", "")
x.replace(")","")
tables.append(x)
print tables;
This prints the table as follows, 这将打印表如下,
[('acam_datasegregationdetails',), ('acam_datasegregationheader',), ('idn_accessinformation',), ('idn_b2cuseraccountmapping',), ('idn_b2cuserdevicemapping',), ('idn_b2cusers',), ('idn_roles',), ('idn_useraccountmapping')]
Needed Output: 所需的输出:
['acam_datasegregationdetails', 'acam_datasegregationheader', idn_accessinformation', 'idn_b2cuseraccountmapping', 'idn_b2cuserdevicemapping', 'idn_b2cusers', 'idn_roles', 'idn_useraccountmapping']
Drop that loop and in instead do 放下该循环并改为
tables = [t[0] for t in tablesWithDetails]
It will build a list containing the first element of each tuple in the result set. 它将构建一个列表,其中包含结果集中每个元组的第一个元素。
Or even simpler (and cheaper), if you want a list then return an array which will be adapted to a list by Psycopg: 甚至更简单(也更便宜),如果您想要一个列表,则返回一个数组,该数组将被Psycopg调整为列表:
cursor.execute("""
select array_agg(relname)
from pg_class
where relkind='r' and relname !~ '^(pg_|sql_)';"
""")
tables = cursor.fetchall()[0][0]
The problem is due this piece of code 问题是由于这段代码
tables.append(x)
When you execute cursor.fetchall()
you will get a List of Tuples 当您执行cursor.fetchall()
您将获得一个元组列表
and when you do for x in tablesWithDetails:
you are iterating over the list by one tuple at a time
并且当您for x in tablesWithDetails:
您one tuple at a time
遍历列表
So when you do tables.append(x)
you are appending a single element tuple to the list 因此,当执行tables.append(x)
时,您tables.append(x)
单个元素元组追加到列表中
To change that you could do this tables.append(x[0])
it appends the first element of the tuple 要更改,您可以执行此表tables.append(x[0])
会附加元组的第一个元素
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