Java：以百分比表示的高分列表

Question

I want to create a list that holds a value and a name. The value is the percentage a player got in two decimals (for instance 0.94) and the name is simply the player's name.

I have this list:

List<Highscore> highscore = new LinkedList<Highscore>(Arrays.asList());

Highscore contains:

String percent;
String name;

What is the best way to sort this list so the highest percentage is first and so forth. I've seen some Comparator methods, but I did not understand them at all and they did not work for me. For instance:

if (highscore.size() > 0) {
    Collections.sort(highscore.size, new Comparator<Campaign>() {
        @Override
        public int compare(final Campaign object1, final Campaign object2) {
            return object1.getName().compareTo(object2.getName());
        }
       } );
   }

Answer 1

Store them in a TreeSet and make the object Comparable with the high score being used to compare first and then name second. (Or use a custom Comparator on the TreeSet that does the same thing). That will have them in a permanently sorted collection.

Otherwise your example is correct except for the Comparator you are using which looks at name not score.

Storing the percentage as an integer (or float) rather than a String will make this easier.

Whatever you do you need a Comparator looking something like:

new Comparator<Campaign>() {
    @Override
    public int compare(final Campaign object1, final Campaign object2) {
        int result = //Compare your scores here - however you store them will change this bit
        if (result != 0) {
             return result;
        }
        // If scores are equal then just return the result of a comparison by name
        return object1.getName().compareTo(object2.getName());
    }
}

The name comparison is needed as otherwise two people with the same score only one would appear in the Set .