如何获取此字符串的 08:00 2015-01-01T08:00:00-02:00

Question

 String date = "2015-01-01T08:00:00-02:00";

and I need get only 08:00

Can you please help to parser this formate?

I tried this code below. but not work

 try {
        String[] buffer = null;
        buffer = dateString.split("T");

        DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");

        return dateFormat.parse(buffer[0]);
    } catch (ParseException e) {
        Log.e("Error", e.getMessage());
        return null;
    }
}

Answer 1

If you're using java-8

String date = "2015-01-01T08:00:00-02:00";
ZonedDateTime ldt = ZonedDateTime.parse(date);
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("HH:mm");
System.out.println(dtf.format(ldt)); // 08:00
// Thank @MadProgrammer for the following ones. :)
System.out.println(ldt.toLocalTime()); // Also prints 08:00
System.out.println(ldt.getHour()+":"+ldg.getMinute()); // Prints 8:0 but you could use 
                                                       // those variable for other things 
                                                       // if you do not need to print them

Answer 2

You need to Convert this to Calendar object and then you can get what ever you want from it.

String dateInString = new java.text.SimpleDateFormat("EEEE, dd/MM/yyyy/hh:mm:ss")
        .format(cal.getTime())
SimpleDateFormat formatter = new SimpleDateFormat("EEEE, dd/MM/yyyy/hh:mm:ss");
Date parsedDate = formatter.parse(dateInString);

Use this date to set it in Calendar. You could use the date object it self but it deprecated https://docs.oracle.com/javase/7/docs/api/java/util/Date.html .

Answer 3

I found the solution

  String date = "2015-01-01T08:00:00-02:00";

  try{
       String[] buffer = null;
       buffer = horaInicio.split("T");
       DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
       dateFormat.parse(buffer[1]);

     }catch (Exception e) {
       Log.e("Error", e.getMessage());
     }