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二进制搜索树忘记了我添加的每个节点

[英]Binary Search Tree Forgetting Every Node I Add

My problem is seemingly simple, but I can't find its solution. 我的问题看似简单,但找不到解决方案。 I have a binary tree, and this is my add function: 我有一棵二叉树,这是我的添加函数:

void collection::addToTree(vendor *& item)
{
    Node * curr = root;
    while (curr)
    {
        if (strcmp(item->getName(), root->item->getName()) < 0)
            curr = curr->left;
        else
            curr = curr->right;
    }
    curr = new Node(item);
}

And this is my Node constructor: 这是我的Node构造函数:

collection::Node::Node(vendor *& item) : left(nullptr), right(nullptr)
{
    this->item = item;
}

However, the tree is always empty, no matter what or how many items I try to add to it. 但是,无论我尝试添加多少个项目,树总是空的。 The only other piece of code I can think of that will help you guys is my struct for my tree: 我可以想到的,这将帮助你们唯一的另一段代码是我的struct为我的树:

struct Node
{
    Node();
    Node(vendor *& item);
    vendor * item;
    Node *left, *right;
};
Node * root;

All of the sub-variables of vendor do have values (as I've seen in my debugger). vendor所有子变量都具有值(如我在调试器中看到的)。 I wish I could give you guys more detail, but this is all I know about the error. 希望我能为您提供更多详细信息,但这只是我对错误的了解。 Any feedback is greatly appreciated. 任何反馈,不胜感激。

add函数中,您仅使curr指向新项,但这并不会变回先前的左/右指针,这可能正是您的目标。

You need to modify the left/right pointers directly, something like this: 您需要直接修改左右指针,如下所示:

void collection::addToTree(vendor *& item)
{
    Node * curr = root;
    while (curr)
    {
        if (strcmp(item->getName(), curr->item->getName()) < 0)
        {
            if (!curr->left)
            {
                curr->left = new Node(item);
                return;
            }
            curr = curr->left;
        }
        else
        {
            if (!curr->right)
            {
                curr->right = new Node(item);
                return;
            }
            curr = curr->right;
        }
    }
    root = new Node(item);
}

Also, make sure you do Node * root = nullptr , as no initializing it can lead to it containing any arbitrary value. 另外,请确保执行Node * root = nullptr ,因为不进行初始化可能会导致它包含任意值。

Notice that I also changed if (strcmp(item->getName(), root->item->getName()) < 0) to if (strcmp(item->getName(), curr->item->getName()) < 0) , as the branching is dependent on curr , not root . 注意我也将if (strcmp(item->getName(), root->item->getName()) < 0)更改为if (strcmp(item->getName(), curr->item->getName()) < 0) ,因为分支取决于curr而不是root

I think the problem here is that your curr variable should be declared as Node **curr and receive the root's address in order for the change to be visible outside of the addToTree function. 我认为这里的问题在于,您的curr变量应声明为Node **curr并接收根的地址,以便在addToTree函数之外可以看到更改。

void collection::addToTree(vendor *& item)
{
    Node ** curr = &root;
    while (*curr)
    {
        if (strcmp(item->getName(), (*curr)->item->getName()) < 0)
            (*curr) = (*curr)->left;
        else
            (*curr) = (*curr)->right;
    }
    *curr = new Node(item);
}

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