[英]PHP,Jquery(ajax) post uncaught syntaxerror:unexpected token <
guys i keep on getting this uncaught syntaxerror:unexpected token <, and it points to the jquery library file,i am making a request to AJAX(comment-insert-ajax.php) using JQuery(comment-insert.js),i try removing the closing token of php(?>) in the AJAX script but i still get the error.I actually get the error when i add the 'require_once' lines,sorry about that. 伙计们,我继续得到这个未捕获的语法错误:意外的令牌<,它指向jquery库文件,我正在使用JQuery(comment-insert.ajax)向AJAX(comment-insert-ajax.php)发出请求,我尝试删除AJAX脚本中php(?>)的结束标记,但我仍然收到错误。当我添加'require_once'行时,我实际上收到了错误,很抱歉。
comment-insert-ajax.php comment-insert-ajax.php
<?php
if(isset($_POST['task']) && $_POST['task'] == 'comment-insert')
{
$userId = (int)$_POST['userId'];
$comment = addslashes(str_replace("\n","<br>",$_POST['comment']));
$std = new stdClass();
$std->comment_id = 24;
$std->userId = $userId;
$std->comment = $comment;
$std->userName = "Thabo Ambrose";
$std->profile_img= "images/tbo.jpg";
require_once $_SERVER['DOCUMENT_ROOT'] . 'defines.php';
require_once MODELS_DIR . 'Comments.php';
echo json_encode($std);
}
else
{
header('location: /');
}
and following is the Jquery file that makes the request using the '$.post' method. 以下是使用'$ .post'方法发出请求的Jquery文件。 comment-insert.js
comment-insert.js
$(document).ready(function(){
$('#comment-post-btn').click(function(){
comment_post_btn_click();
});
});
function comment_post_btn_click()
{
var _comment = $('#comment-post-text').val();
var _userId = $('#user-id').val();
var _userName = $('#user-name').val();
if(_comment.length > 0 && _userId != null)
{
//proceed with ajax call back
$.post("ajax/comment-insert-ajax.php",
{
task : "comment-insert",
userId : _userId,
comment : _comment
}
).error(
function()
{
console.log("Error : ");
}
).success(
function(data)
{
comment_insert(jQuery.parseJSON(data));
console.log("Response text : "+ data);
}
);
console.log(_comment + " "+_userName + " id of "+_userId);
}
else
{
//do something
$('#comment-post-text').addClass('alert alert-danger');
$('#comment-post-text').focus(function(){$('#comment-post-text').removeClass('alert alert-danger');});
}
//remove text in the text area after posting
$('#comment-post-text').val("");
}
function comment_insert(data)
{
var t = '';
t += '<li class="comment-holder" id="_'+data.comment_id+'">';
t += '<div class="user-img">';
t += '<img src="'+data.profile_img+'" class="user-img-pic">';
t += '</div>';
t += '<div class="comment-body">';
t += '<h3 class="username-field">'+data.userName+'</h3>';
t += '<div class="comment-text">'+data.comment+'</div>';
t += '</div>';
t += '<div class="comment-buttons-holder">';
t += '<ul>';
t += '<li class="delete-btn">x</li>';
t += '</ul>';
t += '</div>';
t += '</li>';
$('.comments-holder-ul').prepend(t);
}
The error points to line 7497 of the jQuery library,it point to the following code 错误指向jQuery库的7497行,它指向以下代码
jQuery.parseJSON = function(data)
{
return data;
}
Try using the JSON.parse function: 尝试使用JSON.parse函数:
//proceed with ajax call back
$.post("ajax/comment-insert-ajax.php",
{
task : "comment-insert",
userId : _userId,
comment : _comment
}
).error(
function()
{
console.log("Error : ");
}
).success(
function(data)
{
comment_insert(JSON.parse(data));
console.log("Response text : "+ data);
}
);
console.log(_comment + " "+_userName + " id of "+_userId);
}
try puting the data in a array and then encode it 尝试将数据放入数组,然后对其进行编码
$array = ['comment_id' => 24,'userId' => $userId,'comment' => $comment,'userName' => "Thabo Ambrose",'profile_img'= "images/tbo.jpg"];
echo json_encode($array);
change if(isset($_POST['task']) && $_POST['task'] == 'comment-insert')
this line of code to if(isset($_POST['task']) && isset($_POST['task'])&&$_POST['task']== 'comment-insert')
. 更改
if(isset($_POST['task']) && $_POST['task'] == 'comment-insert')
将这行代码更改为if(isset($_POST['task']) && isset($_POST['task'])&&$_POST['task']== 'comment-insert')
。 then change the ajax call to 然后将ajax调用更改为
$.ajax({
url: "ajax/comment-insert-ajax.php",
data :{"task":"comment-insert","UserId":_userId,"comment":_comment},
type: "POST",
dataType: "json",
success:function(msg) {
}
});
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.