从 jq json 输出中排除列

Question

I would like to get rid of the timestamp<\/code> field here using jq<\/a> JSON processor.

[
  {
    "timestamp": 1448369447295,
    "group": "employees",
    "uid": "elgalu"
  },
  {
    "timestamp": 1448369447296,
    "group": "employees",
    "uid": "mike"
  },
  {
    "timestamp": 1448369786667,
    "group": "services",
    "uid": "pacts"
  }
]

Answer 1

If you just want to delete the timestamps you can use the del() function:

jq 'del(.[].timestamp)' input.json

---

However to achieve the desired output, I would not use the del() function. Since you know which fields should appear in output, you can simply populate an array with group and id and then use the join() function:

jq -r '.[]|[.group,.uid]|join(",")' input.json

-r stands for raw ouput . jq will not print quotes around the values.

Output:

employees,elgalu
employees,mike
services,pacts

Answer 2

For the record, an alternative would be:

$ jq -r '.[] | "\(.uid),\(.group)"' input.json

(The white-listing approach makes it easy to rearrange the order, and this variant makes it easy to modify the spacing, etc.)

The following example may be of interest to anyone who wants safe CSV (ie even if the values have embedded commas or newline characters):

$ jq -r '.[] | [.uid, .group] | @csv' input.json
"elgalu","employees"
"mike","employees"
"pacts","services"

Answer 3

Sed 是你最好的朋友——我想不出更简单的方法，我在这里遇到了与问题作者相同的问题——但也许这是对同一问题的更简单的答案：

< file sed -e '/timestamp/d'