在python中，如何在txt文件中的特定列中搜索特定值，然后返回该特定值的行？

Question

First of all, I have recently started studying python. So I am a beginner.

1111  1  3  
1112  1  2  
1113  2  3  
1114  1  7  
1115  7  2  

Assume I have these values in the text file. As in the title, I want to search a specific column for a specific value in the txt file then return the specific value's row except for the searched "value".

Example:

Search the first column for 1113 value.
Then return 2 3 as:

x = 2
y = 3

Answer 1

You could try this:

import sys
with open( filename, "r" ) as f:
    for line in f:
        parts = line.split(" ")
        if parts[0] == "1113":
            print("x={0} y={1}".format( parts[1], parts[2] ))
            sys.exit(0)

Answer 2

Try something like this:

with open('file.txt', 'r') as f:
    for line in f:
        if line.startswith('1113'):
            line = line.split()
            x = int(line[1])
            y = int(line[2])

as 'file.txt' put your file name and as '1113' put the value you are looking for. good luck

Answer 3

There is a csv module which will do all the dirty work for you:

import csv

def find(filename, number):
    with open(filename) as file:
        reader = csv.DictReader(file,
                                fieldnames=['col1', 'col2', 'col3'],
                                delimiter=' ')
        for line in reader:
            if line['col1'] == str(number):
                return (line['col2'], line['col3'])

if __name__ == '__main__':
    (x, y) = find('data.txt', 1113) or (None, None)
    print(x, y)

Answer 4

I'd prefer:

search_text = '1113'
with open(FileName) as f:
    for i in f:
        if i.strip() != '':
            for j in i.strip().split():
                if j[0] == search_text:
                    x = int(i[1])
                    y = int(i[2])

Answer 5

This will allow you to search for any value on any column.

import csv


def find(reader, col, val):
    for row in reader:
        if row[col] == val:
            return row
    raise ValueError('Value {} not found in row {}'.format(val, col))


def findexcept(reader, col, val):
    r = find(reader, col, val)
    r.pop(col)
    return r

with open('searchdata.txt') as f:
    lines = (line.strip() for line in f)
    c = csv.reader(lines, delimiter=' ', skipinitialspace=True)

    try:
        x = findexcept(c, 0, '1114')
        print(x)
    except ValueError as ve:
        print('Error: {}'.format(ve))