[英]How can I use for loop to count numbers?
I need to count numbers upward and have it print out with a string "then" in between: 5 then 6 then 7 then... like this. 我需要向上计数数字,并用介于两者之间的字符串“ then”将其打印出来:5、6、7,然后……。 I am very confused with using the parameters vs function name when you return.
返回时,我对使用参数vs函数名称感到非常困惑。 My code is below.. but could someone help with this?
我的代码在下面..但是有人可以帮忙吗?
function countUp(start) {
start +=
for(var i = start; i < start + 10; i++) {
console.log(start[i] + "then");
}
return start;
}
I would do something like this: 我会做这样的事情:
function countSheep(limit){
for (var i = 1; i < limit; i +=1){
console.log(i + " sheep")
}
}
countSheep(10);
I used "sheep" instead of "then", but you get the idea. 我使用“绵羊”代替“然后”,但是您明白了。 Since you just want to produce a side effect (print out a "1 then 2.." to the console, you don;t need to build up a string and then have your function return it.
由于您只想产生一个副作用(将“ 1然后2 ..”打印到控制台,因此您无需构建字符串,然后让函数返回它)。
If you did want to build up a string and then have your function return it though, you could do something like this instead: 如果您确实想建立一个字符串然后让函数返回它,则可以执行以下操作:
function countSheep(limit){
var allMySheep = "";
for (var i = 1; i < limit; i +=1){
allMySheep += (i + " sheep, ")
}
return allMySheep;
}
console.log(countSheep(10));
Note: I started my loops at 1 (var i = 1) because I'm counting sheep, not numbers. 注意:我从1(var i = 1)开始循环,因为我是在计算绵羊,而不是数字。 You'd probably want to start yours at 0 (var i = 0).
您可能想从0开始(变量i = 0)。
We can use JavaScript join function as well to achieve this Code 我们也可以使用JavaScript连接功能来实现此代码
function getCountStr(count) {
var str =[];
for (var i = 1; i <= count; i++) {
str.push(i);
}
console.log(str.join(' then '));
}
There are few issues with your code 您的代码很少有问题
function countUp(start) {
start += // <<<<< what's this? It's an incomplete (and useless) statement
for(var i = start; i < start + 10; i++) {
console.log(start[i] + "then");
// ^^^^^^^^ why are doing this? you should only write i
}
return start; // you don't need to return anything
}
A cleaned and working version from your code 您的代码中已清理且可以使用的版本
function countUp(start) {
for(var i = start; i < start + 10; i++) {
console.log(i + " then ");
}
}
But this code will have an extra 'then' at the end like 1 then 2 then
, so here's a code that will handle this 但是此代码的末尾将有一个额外的“ then”,例如
1 then 2 then
,因此这是将处理此问题的代码
function countUp(start) { // a temporary array to store your numbers var tmpArr = []; for (var i = start; i < start + 10; i++) { // store the count into the array tmpArr.push(i); } // display the count by putting ' then ' between each number var stringToDisplay = tmpArr.join(' then '); console.log(stringToDisplay); document.write(stringToDisplay); } countUp(1);
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