如何在 openweather API 中获取地理位置
[英]How do I get geolocation in openweather API
问题描述
How do I get mu openweather API to work with geolocation?
如何让 mu openweather API 与地理定位一起使用？ This is my current html code:这是我当前的 html 代码：
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="http://s3.amazonaws.com/codecademy-content/courses/ltp/css/bootstrap.css">
<link rel="stylesheet" href="main.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type='text/javascript' src='app.js'></script>
</head>
<body>
<div class="jumbotron">
<button onclick="getLocation()">Get my location.</button>
<p id="demo"></p>
<script>
var x = document.getElementById("demo");
function getLocation() {
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(showPosition);
} else {
x.innerHTML = "Geolocation is not supported by this browser.";
}
}
function showPosition(position) {
x.innerHTML = "Latitude: " + position.coords.latitude +
"<br>Longitude: " + position.coords.longitude;
}
</script>
<p>The weather outside is: </p>
<div class= "weather">
Oops.. there is no temperature available for your location right now.
</div>
</div>
</body>
</html>
And my JavaScript code:还有我的JavaScript代码：
$(document).ready(function(){
$.getJSON( "http://api.openweathermap.org/data/2.5/weather?q=Eindhoven&appid=9334f947893792dcb9b2e2c05ae23eb0", function( data ) {
$('.weather').html(Math.round(data.main.temp-273)+ ' degrees Celcius');
});
});
I got the weather in Eindhoven city working, but I want to be able to adjust it to the latitude and longitude.我让埃因霍温市的天气正常工作，但我希望能够将其调整为经纬度。 Can someone fix my code for me?有人可以帮我修复我的代码吗？ And help me?并帮助我？
I know it has something to do with this link: api.openweathermap.org/data/2.5/weather?lat={lat}&lon={lon} but I don't know how to implement my own fount latitude and longitude in it...我知道它与此链接有关：api.openweathermap.org/data/2.5/weather?lat={lat}&lon={lon} 但我不知道如何在其中实现我自己的 fount 纬度和经度...
2 个解决方案
解决方案1
5 2015-11-27 04:55:21
You can get data about the location with use third-party API, for example: http://ip-api.com/您可以使用第三方 API 获取有关位置的数据，例如： http : //ip-api.com/
var getIP = 'http://ip-api.com/json/';
$.getJSON(getIP).done(function(location) {
console.log(location)
})
Next get WeatherData from OpenWeatherMap service using the ip-api that we got above接下来使用我们上面得到的 ip-api 从 OpenWeatherMap 服务获取 WeatherData
var getIP = 'http://ip-api.com/json/';
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
$.getJSON(getIP).done(function(location) {
$.getJSON(openWeatherMap, {
lat: location.lat,
lon: location.lon,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
console.log(weather)
})
})
In this case, the celsius temperature (metric)在这种情况下，摄氏度（公制）
Or using HTML5 Geolocation API (in Google Chrome work only with HTTPS or on localhost )或使用 HTML5 Geolocation API（在 Google Chrome 中仅使用HTTPS或在localhost ）
var openWeatherMap = 'http://api.openweathermap.org/data/2.5/weather'
if (window.navigator && window.navigator.geolocation) {
window.navigator.geolocation.getCurrentPosition(function(position) {
$.getJSON(openWeatherMap, {
lat: position.coords.latitude,
lon: position.coords.longitude,
units: 'metric',
APPID: 'APIKEY'
}).done(function(weather) {
console.log(weather)
})
})
}
解决方案2
0 2020-10-17 11:59:06
Lets try it , I hope that is a better solution to get current weather via using geolacation and Openweather API .让我们尝试一下，我希望这是通过使用 geolacation 和 Openweather API 获取当前天气的更好解决方案。 Simply pass your Openweather API Key , you will get a json array, fetch your location and current weather.只需传递您的 Openweather API Key ，您将获得一个 json 数组，获取您的位置和当前天气。 And you also use your weather icon which you want.您还可以使用您想要的天气图标。
window.addEventListener("load",() =>{
let long;
let lag;
if(navigator.geolocation){
navigator.geolocation.getCurrentPosition((position) =>{
var lat = position.coords.latitude;
var long = position.coords.longitude;
const proxy = "https://cors-anywhere.herokuapp.com/";
const api = `${proxy}api.openweathermap.org/data/2.5/weather?lat=${lat}&lon=${long}&appid=9891731b361e47661f72b06213efbf65`;
fetch(api)
.then((response) =>{
return response.json();
})
.then(data =>{
const {name} = data;
const {feels_like} = data.main;
const {id,main} = data.weather[0];
loc.textContent = name;
climate.textContent = main;
tempValue.textContent = Math.round(feels_like-273);
if(id < 250){
tempIcon.src = './icon/storm.svg'
}
else if(id < 350){
tempIcon.src = './icon/drizzle.svg'
}
else if(id < 550){
tempIcon.src = './icon/rain.svg'
}
else if(id < 650){
tempIcon.src = './icon/snow.svg'
}
else if(id < 800){
tempIcon.src = './icon/atmosphere.svg'
}
else if(id === 800){
tempIcon.src = './icon/clear.svg'
}
else if(id >800){
tempIcon.src = './icon/clouds.svg'
}
console.log(data);
})
})
}
})
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