带有两位小数的输入掩码数字

Question

I'm trying to transform my normal input field unto a numeric input with two decimal places using the great plugin called "inputmask" by awesome "RobinHerbots", below snippet is what I tried but sadly and unfortunately its not working, any ideas, help please?

 $(document).ready(function(){ $('.decimal').inputmask('decimal', { rightAlign: false, digits: 2, placeholder: "0" }); });

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <script src="https://rawgit.com/RobinHerbots/jquery.inputmask/3.x/dist/jquery.inputmask.bundle.js"></script> <input type="text" class="decimal form-control" />

Answer 1

$('.decimal').inputmask({ mask: "99.99"}) // As you requested

OR

$('.decimal').inputmask({ mask: "99.9{2}"}) //Same as the first one, {2} mean preceding char count MUST be 2

OR

$('.decimal').inputmask({ mask: "(99)|(99.9{1,2})"}) //We use optional here so user can enter 99 or 99.9 or 99.99

Answer 2

Try this

https://jsfiddle.net/Ln375fmz/

 $('.decimal').inputmask({ mask: "9{0,20}Z9{2}", definitions: { "Z": { validator: "[.]", } }, clearIncomplete: true, autoUnmask: true, placeholder: "", });

 <input type="text" id="money">