[英]Serialize to object using scala mongo driver?
I'm new to the scala mongo driver and am trying to understand how to map a class from a Document?我是 scala mongo 驱动程序的新手,想了解如何从文档映射类? None of the documentation seems to show how this is done.
似乎没有任何文档显示这是如何完成的。 In the .net driver, its as easy as passing a generic and having fields auto mapped.
在 .net 驱动程序中,它就像传递泛型和自动映射字段一样简单。 Is there nothing similar in scala?
Scala 中没有类似的东西吗?
They don't make it easy.他们并不容易。 Digging through the java, I came up with this solution:
通过java挖掘,我想出了这个解决方案:
import org.bson.codecs.DecoderContext
import org.bson.codecs.configuration.CodecRegistries.{fromProviders, fromRegistries}
import org.bson.codecs.configuration.CodecRegistry
import org.bson.{BsonDocumentReader, BsonDocumentWrapper}
import org.mongodb.scala.bson.codecs.{DEFAULT_CODEC_REGISTRY, Macros}
import org.mongodb.scala.bson.collection.mutable.Document
import scala.reflect.classTag
case class Person(firstName: String, lastName: String)
object MongoTest extends App {
val personCodecProvider = Macros.createCodecProvider[Person]()
val codecRegistry: CodecRegistry = fromRegistries(fromProviders(personCodecProvider), DEFAULT_CODEC_REGISTRY)
val document = Document("firstName" -> "first", "lastName" -> "last")
val bsonDocument = BsonDocumentWrapper.asBsonDocument(document, DEFAULT_CODEC_REGISTRY)
val bsonReader = new BsonDocumentReader(bsonDocument)
val decoderContext = DecoderContext.builder.build
val codec = codecRegistry.get(classTag[Person].runtimeClass)
val person: Person = codec.decode(bsonReader, decoderContext).asInstanceOf[Person]
println(s"person: $person")
}
Example for serializing and deserializing object using mongo macro handler.使用 mongo 宏处理程序序列化和反序列化对象的示例。
import reactivemongo.api.bson.{BSON, BSONDocument, Macros}
case class Person(name:String = "SomeName", age:Int = 20)
implicit val personHandler = Macros.handler[Person]
//Serialize
val bsonPerson = BSON.writeDocument[Person](Person())
println(s"${BSONDocument.pretty(bsonPerson.getOrElse(BSONDocument.empty))}")
//Deserialize
val bsonDocumentPerson = BSONDocument("name"-> "MyNameHere", "age"->35)
val scalaObjPerson: Person = BSON.read[Person](bsonDocumentPerson).getOrElse(Person())
printf(s"Scala person obj = $scalaObjPerson")
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