警告：PHP 中的除以零

Question

https://ctrlv.cz/c7pu

The error I am receiving, I don't understand why though. I have a feeling that it is something to deal with the $bank variable but I am quite new with PHP and I don't quite understand all of the code:

PHP:

<?php

  $thisgame = fetchinfo("value","info","name","current_game");
  $bank = fetchinfo("cost","games","id",$thisgame);

  $thisuserid=$rsx['uid'];

  $result = mysql_query("SELECT SUM(value) AS value FROM `game$thisgame` WHERE `userid`='$thisuserid'");
  $getrowval = mysql_fetch_assoc($result);
  $generatechance=round($getrowval["value"]*100/$bank,1);
  $howmanyitems=mysql_num_rows(mysql_query('SELECT * FROM `game'.$thisgame.'` WHERE   `userid`="'.$thisuserid.'"'));

  $profilele='http://steamcommunity.com/profiles/'.$thisuserid;
?>

Those are lines 77 to 90 so.... Anyone have an idea?

Answer 1

replace $generatechance=round($getrowval["value"]*100/$bank,1); with and let me know if it works

if( $bank > 0 ){
    $generatechance=round($getrowval["value"]*100/$bank,1);
}else{
    $generatechance = <YOU NEED TO DO THIS PART>
}

more better idea will be $bank = fetchinfo("cost","games","id",$thisgame); after this line check if you are getting $bank or not.

check if $result = mysql_query("SELECT SUM(value) AS value FROM game$thisgame WHERE userid ='$thisuserid'"); query is correct game$thisgame .