如何在 Windows 批处理文件中打印上次执行的应用程序的退出代码？

Question

I have a Unix shell script with the following code, which I want to turn into a Windows batch file:

./test.sh some arguments here

export a=$?
echo "RETURN CODE FROM UpgradeR16 = $a" 

I've already rewritten test.sh into test.bat , but I'm not sure what the export and echo are doing here. How do I write the equivalent code in a Windows .bat file?

Answer 1

If by $? is ment to be the return value of the last execution then this needs to be replaced with %ERRORLEVEL% in a windows batch file.

So you could just use echo "RETURN CODE FROM Upgrade16 = %ERRORLEVEL%"