[英]How to get and use a JSON parameter value from an API request/response
I'm working on a website and want to display or hide a div-tag depending on a parameter value I can find in an API response. 我在一个网站上工作,并且想要显示或隐藏div标签,具体取决于我可以在API响应中找到的参数值。
The link to the API information I need is https://api.hitbox.tv/media/status/masta where "masta" is replaced by my channel-name. 我需要的API信息的链接是https://api.hitbox.tv/media/status/masta ,其中“ masta”被替换为我的频道名称。 The response looks like this:
{"media_is_live":"0","media_views":"2"}
响应如下所示:
{"media_is_live":"0","media_views":"2"}
I prefer to only use pure javascript, but tried the code below using AJAX but didn't work. 我更喜欢只使用纯JavaScript,但使用AJAX尝试了以下代码,但没有用。 I'm not familiar with javascript, jQuery and AJAX so maybe I did some wrong code writing as well.
我不熟悉javascript,jQuery和AJAX,所以也许我也写了一些错误的代码。 Any suggestions?:
有什么建议么?:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script>
$(document).ready(function() {
$.ajax({
type: "GET",
dataType: "json",
url: "https://api.hitbox.tv/media/status/masta",
data: "media_is_live",
success: function(data){
if(data == "0") {
document.getElementById("player").style.visibility = "hidden";
}
else {
document.getElementById("player").style.visibility = "visible";
}
}
});
});
</script>
<div id="player">[LIVESTREAM-PLAYER]</div>
Your ajax call should look like this. 您的ajax调用应如下所示。
The media_is_live is in the result, not in your query. media_is_live在结果中,而不在您的查询中。
$.ajax({
type: "GET",
dataType: "json",
url: "https://api.hitbox.tv/media/status/masta",
success: function(data){
if(data.media_is_live == "0") {
//Your code here
}
else {
//Your code here
}
}
});
Try: 尝试:
$(document).ready(function() {
$.ajax({
type: "GET",
dataType: "json",
url: "https://api.hitbox.tv/media/status/masta",
success: function(data){
if(data.media_is_live === "0") {
document.getElementById("player").style.visibility = "hidden";
}
else {
document.getElementById("player").style.visibility = "visible";
}
}
});
});
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