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如何使sql查询按日期分组和求和?

[英]How to make sql query to group and sum results by date?

In yii2 app I have Payment model with fields id (primary key), u_id (integer, means id of person that made this payment from User model), sum (integer) and date . 在yii2应用程序中,我有Payment模型,字段id (主键), u_id (整数,表示从User模型进行此付款的人的ID), sum (整数)和date Example: 例:

+--------------------------------+
| Payment                        |
+--------------------------------+
| id | u_id | sum  | date        |
+--------------------------------+
| 1  | 1    | 400  | 2015-11-25  |
| 2  | 1    | 200  | 2015-11-25  |
| 3  | 2    | 500  | 2015-11-25  |
| 4  | 2    | 300  | 2015-11-25  |
| 5  | 1    | 100  | 2015-11-20  |
+--------------------------------+

Q: I want to group results by date and summarize sum fields of all rows for each u_id for every day and also show total row. 问:我想按日期对结果进行分组,并为每天的每个u_id汇总所有行的sum字段,并显示total How to do that...? 怎么做...? Maybe without total row? 也许没有total排? On yii2 or clean mysql . 在yii2 或干净的mysql Example of results: 结果示例:

+-------------------------------------+
| Date       | User id | Money, $     |
+-------------------------------------+
| 2015-11-25 |         | 1400 (total) |
| 2015-11-25 | 1       | 600          |
| 2015-11-25 | 2       | 800          |
| 2015-11-20 |         | 100 (total)  |
| 2015-11-20 | 1       | 100          |
+-------------------------------------+

Payment model: Payment

public function search($params)
{
    $query = Payment::find();

    // do we need to group and sum here?

    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    $this->load($params);

    return $dataProvider;
}

I guess ListView will be easer then GridView , because we will be able to make some calculations for each result. 我想ListView会比GridView更容易,因为我们将能够为每个结果进行一些计算。 View: 视图:

<table>
    <thead>
        <tr>
            <th>Date</th>
            <th>User id</th>
            <th>Money, $</th>
        </tr>
    </thead>
    <tbody>
        <?= ListView::widget([
            'dataProvider' => $dataProvider,
            'itemView' => '_item_view',
        ]) ?>
    </tbody>
</table>

_item_view : _item_view

<tr>
    <td><?= $model->date ?></td>
    <td><?= $model->u_id ?></td>
    <td><?= $model->sum ?></td>
</tr>

Try this way: 试试这种方式:

select dt "Date", usr "User Id", 
      case when usr is null 
           then concat(money, ' (total)')
           else money
           end as "Money, $"
  from (
     select dt, null as usr, sum(vsum) as money
       from mytable
      group by dt
     union
     select dt, u_id, sum(vsum) as money
       from mytable
      group by dt, u_id
   ) a
  order by dt desc, coalesce(usr,0)

See it here: http://sqlfiddle.com/#!9/48102/6 请在此处查看: http//sqlfiddle.com/#!9/48102/6

What you need in plain MySql would be possible with analytical functions but since MySql doesn't support it, you have to emulate it. 你可以在普通的MySql中使用分析函数,但由于MySql不支持它,你必须模拟它。

In my solution, I've made a query that sum the money only by date 在我的解决方案中,我提出了一个只按日期汇总钱的查询

select dt, null as usr, sum(vsum) as money
  from mytable
 group by dt

The null as usr column is needed so I can use the UNION operator with the second part. 需要null as usr列,因此我可以将UNION运算符与第二部分一起使用。 This query will get all dates and money summed. 此查询将汇总所有日期和金额。

Then the second part 然后是第二部分

select dt, u_id, sum(vsum) as money
  from mytable
 group by dt, u_id

Wich will get all dates by user summing the money. Wich将通过用户总结钱来获取所有日期。

The third part is to make it as subquery so I can order it with by date, user. 第三部分是使它成为子查询,所以我可以按日期,用户订购它。 Remember that the user of the first part is null, so I make it so every as null become 0 so it will be shown first. 请记住,第一部分的用户是null,所以我这样做,所以每当null变为0所以它将首先显示。

You can use a SqlDataProvider this way 您可以这种方式使用SqlDataProvider

$count = Yii::$app->db->createCommand('
    SELECT COUNT(*) FROM payment group by `date`, u_id', )->queryScalar();

$dataProvider = new SqlDataProvider([
    'sql' => 'SELECT u_id, sum(`sum`)  as `sum` , `date`   FROM payment group by `date`, u_id',

    'totalCount' => $count,
    'sort' => [
        'attributes' => [
            'u_id',
            'sum',
            'date',
        ],
    ],
    'pagination' => [
        'pageSize' => 20,
    ],
]);

 return $this->render('index', [
        'dataProvider' => $dataProvider,
    ]);

One option is let mysql calculate the totals using WITH ROLLUP . 一个选项是让mysql使用WITH ROLLUP计算总数。

select dt, u_id, sum(vsum)
from   payment
group by dt, u_id with rollup;

+------------+------+-----------+
| dt         | u_id | sum(vsum) |
+------------+------+-----------+
| 2015-11-20 |    1 |       100 |
| 2015-11-20 | NULL |       100 |
| 2015-11-25 |    1 |       600 |
| 2015-11-25 |    2 |       800 |
| 2015-11-25 | NULL |      1400 |
| NULL       | NULL |      1500 |
+------------+------+-----------+

If you don't want the overall total, you can eliminate that as well. 如果你不想要整体总数,你也可以消除它。

select * from (
    select dt, u_id, sum(vsum)
    from   payment
    group by dt, u_id with rollup
) q where dt is not null;

+------------+------+-----------+
| dt         | u_id | sum(vsum) |
+------------+------+-----------+
| 2015-11-20 |    1 |       100 |
| 2015-11-20 | NULL |       100 |
| 2015-11-25 |    1 |       600 |
| 2015-11-25 |    2 |       800 |
| 2015-11-25 | NULL |      1400 |
+------------+------+-----------+

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