如何在没有提升deadline_timer的情况下将boost :: asio代码完全转换为C ++ 11 / asio？

Question

My goal is to have my project to use the " asio " library without Boost, but use C++11. The example is to convert this server code to use Timeout.

Here is what I did:

1. boost::bind -> std::bind , _1 -> std::placeholders::_1
2. most boost::asio::xxx -> asio::xxx
3. boost::system::error_code -> asio::error_code

Now, there is 12 errors left all about deadline_timer :

deadline_timer input_deadline_;
input_deadline_.expires_at(boost::posix_time::pos_infin);
...
void check_deadline(deadline_timer* deadline)
{
    ...

    if (deadline->expires_at() <= deadline_timer::traits_type::now())

What is the correct code to use? I am using GCC 4.9.1/2, and newly downloaded asio library 1.10.6.

Answer 1

You can use high_resolution_timer instead, which uses std::chrono on C++11 compilers:

#if defined(GENERATING_DOCUMENTATION)
/// Typedef for a timer based on the high resolution clock.
/**
 * This typedef uses the C++11 @c <chrono> standard library facility, if
 * available. Otherwise, it may use the Boost.Chrono library. To explicitly
 * utilise Boost.Chrono, use the basic_waitable_timer template directly:
 * @code
 * typedef basic_waitable_timer<boost::chrono::high_resolution_clock> timer;
 * @endcode
 */
typedef basic_waitable_timer<
    chrono::high_resolution_clock>
  high_resolution_timer;
#elif defined(ASIO_HAS_STD_CHRONO)
typedef basic_waitable_timer<
    std::chrono::high_resolution_clock>
  high_resolution_timer;
#elif defined(ASIO_HAS_BOOST_CHRONO)
typedef basic_waitable_timer<
    boost::chrono::high_resolution_clock>
  high_resolution_timer;
#endif

} // namespace asio