Java服务器套接字

Question

I got a minor issue. I want to use serversockets to send over a list of players to a client. But for some reason when I try to run the application it will stop at when it reaches socket = serverSocket.accept(); . I tried serval things on google but doesn't work.

package Serverside;
import java.io.*;
import java.net.*;
import com.mygdx.game.Sprites.Hero;
import com.mygdx.game.Sprites.Player;
import java.util.ArrayList;
/**
 *
 * @author Tjidde Nieuwenhuizen
 */
public class ServerArenaOfLegends {
    static ServerSocket serverSocket;
    static Socket socket;
    static ObjectOutputStream outStreamObj;
    static ObjectInputStream inStreamObj;
    static ArrayList<Player> playerList;
    public static void main(String[] args) {
        ServerArenaOfLegends sr = new ServerArenaOfLegends();
        sr.run();
    }
    private void run() {
        playerList = new ArrayList<Player>();
        Player p1;
        Hero hero = new Hero(2, null, 3);
        p1 = new Player(null, null, hero);
        playerList.add(p1);
        try {
            serverSocket = new ServerSocket(5555);
            socket = serverSocket.accept();
            outStreamObj = new ObjectOutputStream(socket.getOutputStream());
            while (true) {
                outStreamObj.writeObject(playerList);
            }
        } catch (Exception ex) {
            System.out.println(ex.toString());
        }
    }
}

Answer 1

If you run this example :

public static void main(String[] args) {

        try {
            ServerSocket serverSocket = new ServerSocket(5555);
            Socket socket = serverSocket.accept();
            System.out.println("DONE");
        } catch (IOException ex) {
            System.out.println(ex.getMessage());
        }
    }

The program will appear to hang.

Then on the command line run "telnet 127.0.0.1 5555" The program will then print "DONE" and then end.

So .accept() blocks until it gets data and this is the behavior you are seeing.