用于社会安全号码验证的Javascript正则黑名单组合

Question

I have a simple social security number regex ^\\(?\\d{3}\\)?[- ]?\\d{2}[- ]?\\d{4}$

I'd like to blacklist some combinations of numbers for each of the three groups of numbers. Specifically I'd like to accomplish the following 3 conditions.

1. First 3 digits cannot be 000, 666 or larger than 899
2. 4th and 5th digits cannot be 00
3. Last 4 digits cannot be 0000

Answer 1

if (!ssn.match(/^((000|666|9\d{2})-\d{2}-\d{4}|\d{3}-00-\d{4}|\d{3}-\d{2}-0{4})$/)) {
  ...
}

where ssn is a string containing the SSN.

This regex works in 3 parts, each of which corresponds to your conditions.

1. (000|666|9\\d{2})-\\d{2}-\\d{4} matches any SSN starting with 000 , 666 , or 9XX
2. \\d{3}-00-\\d{4} matches any SSN with 00 in the middle
3. \\d{3}-\\d{2}-0{4} matches any SSN with 0000 in the end

The ^ in the beginning and $ at the end force an exact match of ssn . You can omit these if you're searching as a substring.

The ( and ) grouping operators in conjunction with | allow for any of the | separated options to match.

If a SSN doesn't match any of these three, then it passes your conditions

Answer 2

先前的答案很正确，但是RegEx本身可能更简单：

/^(?:000|666|9\d\d)|^\d{3}-?00|0{4}$/

Answer 3

我在这里找到了一个很好的正则表达式

/^(?!000)(?!666)(?!9)\\d{3}([- ]?)(?!00)\\d{2}\\1(?!0000)\\d{4}$/