PrintStream 类型中的方法 println(int) 不适用于参数 (String, int, int, int)

Question

public static void main(String[] args) {
    int num1 = 1;
    int num2 = 1;
    int result = num1 * num2; 
    System.out.println("%d x %d = %d\n",num1,num2,result);
}

I am trying to printout a form like "1 * 10 = 10". However I get an error:

The method println(int) in the type PrintStream is not applicable for the arguments (String, int, int, int)".

I don't know what's the problem and how should I change it?

Answer 1

Try

System.out.println(num1+" x "+num2+" = "+result+"\n");

UPDATE: Some of you are saying this concatenation method is slower than other methods. You are right, it is slower, but does it really matter for this example?

This method is usually used to debug, not as part of the final code, and usually only once or twice on the whole code.

Faster method:

System.out.printf("%d x %d = %d\n",num1,num2,result);

Answer 2

Have you tried using system.out.format like this:

System.out.format("%s x %s = %s\n",num1,num2,result);

Your current solution using println isn't working as println cannot format text output in this way, you would have to (as others have said) concatenate the string using the "+" operator. It's slower in most cases but for debugging purposes I shouldn't imagine it's much of a problem either way.

Answer 3

System.out中有一个printf(...)方法！

System.out.printf("%d x %d = %d\n",num1,num2,result);

Answer 4

The Method your using (System.out.println ) isn't made for multiple parameters. By using , you try to give it multiple parameters. You need the + -operator.

Applied to your code it should look like that:

System.out.println(num1 + " x " + num2 + " = " + result);

Maybe you should look at this . This is the Documentation of PrintStream. As you can see there is no method like you are using it( System.out.println(String, Int, Int ,Int); ).

Answer 5

One of the simple way is that you can use the concatenation operation '+' instead of ',' to print

 public static void main(String[] args) {
        // TODO Auto-generated method stub
        int result = 0;
        for(int num1 = 1;num1 < 10;num1++){
            for(int num2 = 1;num2 <10;num2++){
                result = num1 * num2; 
                System.out.println(num1+"x"+num2+"="+result);
            }
        }
    }

}

Answer 6

println as documented here currently accepts 0 or 1 arguments, reason for the mentioned error.

You need to either concatenate or use String Format to format the result if you intend to use println(only):

• String Format: System.out.println(String.format("%dx %d = %d\n",num1,num2,result));

• String Concatenation using StringBuffer: StringBuffer resltBuffer = new StringBuffer(num1).append(" x ").append(num2).append(" = ").append(result); System.out.println(resltBuffer.toString()); StringBuffer resltBuffer = new StringBuffer(num1).append(" x ").append(num2).append(" = ").append(result); System.out.println(resltBuffer.toString());

Answer 7

enter code here


    int first = 20;
    int second = 30;
    System.out.println("before swap");
    System.out.println("first value :" +first);
    
    System.out.println("second value: " +second);
    first = first - second;
    second = first + second;
    first = second - first;
    
    System.out.println("after swap");
  System.out.println("first value: " +first);
    
    System.out.println("second value: " +second);

remove comma from the print statement