打印 json 对象中的所有路径

Question

What is the easy way to get all paths in the Given Json Object; For Example:

{  
   app:{  
      profiles:'default'
   },
   application:{  
      name:'Master Service',
      id:'server-master'
   },
   server:{  
      protocol:'http',
      host:'localhost',
      port:8098,
      context:null
   }
}

I should able to produce the following object

app.profiles=default
application.name=Master Service
application.id=server-master

I was able to achieve the same using a recursive function. I want to know is there any built in function from json which does this.

Answer 1

You can implement your custom converter by iterating through objects recursively.

Something like this:

 var YsakON = { // YsakObjectNotation stringify: function(o, prefix) { prefix = prefix || 'root'; switch (typeof o) { case 'object': if (Array.isArray(o)) return prefix + '=' + JSON.stringify(o) + '\\n'; var output = ""; for (var k in o) { if (o.hasOwnProperty(k)) output += this.stringify(o[k], prefix + '.' + k); } return output; case 'function': return ""; default: return prefix + '=' + o + '\\n'; } } }; var o = { a: 1, b: true, c: { d: [1, 2, 3] }, calc: 1+2+3, f: function(x) { // ignored } }; document.body.innerText = YsakON.stringify(o, 'o');

That's not a best converter implementation, just a fast-written example, but it should help you to understand the main principle.

Here is the working JSFiddle demo .

Answer 2

I think there is no built-in function that does this. It can be done with a simple for loop as below in my fiddle. But it does not take care of recursiveness. Here are other posts that i found regarding the same : Post1 and Post2 and Post3

var myjson = {  
   app:{  
      profiles:'default'
   },
   application:{  
      name:'Master Service',
      id:'server-master'
   },
   server:{  
      protocol:'http',
      host:'localhost',
      port:8098,
      context:null
   }
};

for(key in myjson) {  
  for(k in myjson[key]) {
    console.log(key + '.' + k + ' = '+ myjson[key][k]);
  }  
}

Fiddle

Answer 3

var obj1 = {
    "name" : "jane",
    "job" : {
        "first" : "nurse",
        "second" : "bartender",
        "last" : {
            "location" : "Paris",
            "work" : ["sleep", "eat", "fish", {"math" : "morning", "chem" : "late night"}],
            "read_books": {
                "duration" : 10,
                "books_read" : [{"title" : "Gone with the wind", "author": "I don't know"}, {"title": "Twologht", "author": "Some guy"}]
            }
        }
    },
    "pets": ["cow", "horse", "mr. peanutbutter"],
    "bf" : ["jake", "beatles", {"johnson": ["big johnson", "lil johnson"]}]    
}

var obj2 = ["jane", "jake", {"age" : 900, "location": "north pole", "name" : "Jim", "pets" : "..."}];

var allRoutes = [];

function findTree(o, parentKey = '', parentObject)
{
    if (typeof o !== 'object')
    {
        if (parentKey.substr(0,1) === '.')
            allRoutes.push(parentKey.substr(1));
        else
        allRoutes.push(parentKey);

        return;
    }

    let keys = Object.keys(o);

    for (let k in keys)
    {
        findTree(o[keys[k]], Array.isArray(o) ? parentKey + "[" +keys[k] + "]" :  parentKey + "." +keys[k], o);     
        //findTree(o[keys[k]], parentKey + "[" +keys[k] + "]");     
    }
}

findTree(obj1);

Try this.