[英]Unsequenced modification warning becomes result unused warning in C++11
I'm experimenting with this filters library, and getting an unsequenced modification warning from the following snippet. 我正在尝试使用此过滤器库,并从以下代码段中收到无序的修改警告。
while (--numSamples >= 0)
*dest++ = state.process(*dest, *this);
This makes sense looking at similar questions on SO, as dest is being modified and accessed in the same command. 当在同一命令中修改和访问dest时,在SO上查看类似的问题就很有意义。 So, I guess the intended functionality is the following .
因此,我想预期的功能如下。 .
。 .
。
while (--numSamples >= 0) {
*dest = state.process(*dest, *this);
*dest++;
}
However, this gives a new, more curious warning "warning: expression result unused" for the post increment. 但是,这为发布增量给出了一个新的,更奇怪的警告“警告:表达式结果未使用”。 Why this new warning, and how should I fix this correctly?
为什么会出现此新警告,以及如何正确解决此问题?
*dest++
increments dest
, and dereferences the prior value of dest
. *dest++
增量dest
,并且取消引用的先前值dest
。 The increment is a side effect that you want, the dereference has no effect. 增量是所需的副作用,取消引用无效。 Just write it as
dest++
(or ++dest
). 只需将其编写为
dest++
(或++dest
)即可。
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