[英]mysql query comparing 2 date ranges
here's my data structure: 这是我的数据结构:
seasons
id from to name
----------------------------------------
1 2015-11-01 2015-12-15 season1
2 2015-12-16 2015-12-30 season2
3 2015-12-31 2016-01-20 season3
rooms_free
id from to room_id
----------------------------------------
1 2015-11-26 2015-11-30 1
2 2015-12-19 2015-12-28 2
3 2015-12-22 2015-12-29 3
i need an sql query which will join both tables by date range returning the following result: 我需要一个SQL查询,该查询将按日期范围连接两个表,并返回以下结果:
id_room room_from room_to season_id season_name
-------------------------------------------------------------
1 2015-11-26 2015-11-30 1 season1
2 2015-12-19 2015-12-28 2 season2
3 2015-12-22 2015-12-29 2 season2
could this be done using normal statements or would i need a mysql function? 可以使用普通语句完成此操作,还是需要mysql函数? any ideas? 有任何想法吗?
ps: the really tricky part is when there's several seasons per room .. ps:真正棘手的部分是每个房间有几个季节时..
This is the best explanation about overlaping data ranges 这是有关重叠数据范围的最佳解释
Determine Whether Two Date Ranges Overlap 确定两个日期范围是否重叠
SELECT rf.room_id as id_room ,
rf.from as room_from,
rf.to as room_to,
s.id as season_id,
s.name as season_name
FROM rooms_free rf
JOIN seasons s
ON (rf.From <= s.to) and (rf.to >= s.from)
OUTPUT OUTPUT
| room_id | from | to | id | name |
|---------|----------------------------|----------------------------|----|---------|
| 1 | November, 26 2015 00:00:00 | November, 30 2015 00:00:00 | 1 | season1 |
| 2 | December, 19 2015 00:00:00 | December, 28 2015 00:00:00 | 2 | season2 |
| 3 | December, 22 2015 00:00:00 | December, 29 2015 00:00:00 | 2 | season2 |
SELECT rooms_free.id as id_room, rooms_free.from as room_from , rooms_free.to as room_to, seasons.id as season_id, seasons.name as season_name FROM rooms_free
join seasons on rooms_free. 选择Rooms_free.id作为id_room,并将rooms_free.from作为room_from,rooms_free.to作为room_to,seasons.id作为season_id,seasons.name作为season_name FROM rooms_free
在rooms_free中加入季节。 from
>=seasons.from and rooms_free. from
> = seasons.from和rooms_free。 to
<=seasons.to to
<= seasons.to
select rooms_free.id as id_room, rooms_free.from as room_from, rooms_free.to as room_to, seasons.id as season_id, seasons.name as season_name
from rooms_free
join seasons
on ((rooms.from <= seasons.from) and (seasons.from <= rooms.to)) or ((seasons.from <= rooms.from) and (rooms.from <= seasons.to))
The statement above checks for strict overlapping. 上面的语句检查是否存在严格的重叠。 If there are several seasons per room, then you can use group by
, having
and group_concat
. 如果有每间客房的几个赛季,那么你可以使用group by
, having
和group_concat
。
Select rooms_free.id, rooms_free.from, rooms_free.to, seasons.id, seasons.name
from rooms_free , seasons
where (rooms_free.from >= season.from and rooms_free.to <= seasons.to)
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