如何将month（int）转换为月份名称（字符串）

Question

I'm having a problem with a function i'm working on. I am able to get the proper data, just not print out the names of the month as well.

sample output i'm getting:

|   Month   | High  |  Low  |  Avg  | Precip  |
|-----------|-------|-------|-------|---------|
1    | 9.8 | -26.2 | -7.8 | 55.3    |
2    | 7.5 | -23.3 | -8.6 | 33.1    |
3    | 14.2 | -19.6 | -4.7 | 33.2   |
4    | 23.7 | -5.3 | 6.2 | 56.8 |
5    | 33.0 | -0.6 | 13.9 | 62.7    |
6    | 32.1 | 8.0 | 19.7 | 69.7 |
7    | 34.9 | 12.6 | 22.2 | 181.8   |
8    | 31.5 | 11.0 | 20.9 | 69.2    |
9    | 34.1 | 5.0 | 16.1 | 69.0 |
10    | 24.8 | -2.9 | 10.8 | 56.9   |
11    | 16.0 | -12.8 | 2.1 | 36.2   |
12    | 15.6 | -17.8 | -4.2 | 65.8

I want to conver digits 1-12 to there proper month names. Ie: 1 = January.

void printMonthlyStatistic(int month,const struct MonthlyStatistic* monthly)

is what the function looks like

for(i=0;i<12;i++){
   printMonthlyStatistic(i+1,&monthly[i])

and is called in main as such.

Any help onto where to look for the proper method to complete this would be great. Thanks!

Answer 1

You should use an array to store the name of the month, like:

const char * months[12] = {"January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"};

You can get the name of the month easily, for example, if index = 1 , then

months[index -1]

will give you the first month name: January .

---

The following code:

for (int i = 0; i < 12; ++i) {
    printf("%s ", months[i]);
}

will output:

January February March April May June July August September October November December

Answer 2

You can maintain Month Array of String like
char months_names[12] = {Jan, Feb, Mar, Apr, Jun, Jul, Aug, Sep, Oct, Nov, Dec};

You can Just paas integer number month to array for getting String value

months_names["Integrer Value"] You will get String name of month.