[英]MySQL - GROUP BY and display only duplicated
I have a log table with username and which browser was used. 我有一个带有用户名和使用哪个浏览器的日志表。 I want select only users that have access by different browsers.
我只想选择可以通过不同浏览器访问的用户。 Example:
例:
|-----------------------|
| username | browser |
|-----------------------|
| user1 | Chrome |
| user1 | Chrome |
| user1 | Firefox |
| user1 | Firefox |
| user1 | Firefox2 |
| user2 | Safari |
| user2 | Safari |
| user2 | Safari |
| user3 | Safari |
| user3 | Chrome |
| user3 | Chrome |
| user3 | Chrome |
|-----------------------|
Query need return only dates from user1 and user3, because they are using different browsers. 查询只需要返回user1和user3的日期,因为它们使用的是不同的浏览器。 Like:
喜欢:
|-----------------------|
| username | browser |
|-----------------------|
| user1 | Chrome |
| user1 | Firefox |
| user1 | Firefox2 |
| user3 | Safari |
| user3 | Chrome |
|-----------------------|
Use group by
with having
. 与
having
使用group by
。
select distinct username, browser
from logtable
where username in (select username from logtable
group by username
having count(distinct browser) > 1)
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