[英]Read integers until EOF in C
I need to read all integers until the EOF. 我需要读取所有整数,直到EOF。 I'm trying this code and the problem is that the program doesn't detect the EOF and keeps running.
我正在尝试此代码,问题是该程序未检测到EOF并保持运行。 What I need is to receive all the data and proceed to the next line of code automatically (the code works with pressing Ctrl-D after the input).
我需要的是接收所有数据并自动进入下一行代码(在输入后按Ctrl-D即可运行代码)。
int x, sum = 0;
while (scanf("%d", &x) == 1) {
sum += x;
}
if (feof(stdin)) {
printf ( "SUM: %d\n", sum );
} else {
printf("ERROR\n");
}
return 0;
How do you want to specify EOF? 您要如何指定EOF?
^D
is the way to do it in the terminal in Unix. ^D
是在Unix终端中执行此操作的方法。 In the Windows terminal, ^Z
does the same thing. 在Windows终端中,
^Z
执行相同的操作。 scanf
will return -1
and feof()
will be non zero. scanf
将返回-1
, feof()
将为非零。 But any further input from stdin will fail too. 但是任何来自stdin的输入也会失败。
Do you want to just hit the enter key? 您是否只想按Enter键? If so, you have to check for that after
scanf
, otherwise the next call to scanf
will read the linefeed and ignore it. 如果是这样,你必须检查,经过
scanf
,否则下次调用scanf
将读取换行,并忽略它。
If you type something that is neither white space nor a number, scanf
will return 0
and leave the unmatched character in the input stream. 如果键入的内容既不是空格也不是数字,则
scanf
将返回0
,并将不匹配的字符保留在输入流中。 Your program will print ERROR
. 您的程序将显示
ERROR
。 Is this what is happening? 这是怎么回事吗?
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.