如何从npm运行的bash脚本中在$ 1之前打印$ 2？

Question

so i'm confused about the relationship between my custom npm scripts and the bash scripts they run. EDIT : i don't think this an isolated bash issue. i can produce the expected behavior described below by writing echo $2 $1 into an .sh file and running it directly from the terminal

for example

"scripts": {"report":"echo $2 $1"}

if i run it from the terminal: npm run report "first" "second" because in my npm script, i call $2​ BEFORE​ $1 , i expect it to output this: second first , but for some reason it always prints $1 first: first second (edited)

i tried a workaround by caching my arguments as variables and then print those:

"scripts": {"report": "(FIRST=$1 && SECOND=$2) && echo $SECOND $FIRST"}

but same output: npm run report "first" "second" => first second

what gives?

Answer 1

The following bash file works good for me:

echo $2 $1

Run with:

bash file.sh 1 2

Output:

2 1

EDIT*:

The problem is with the way you try to use node. It seems the $X variables are not populated by node. It just appends your arguments to the rest of your command.

EDIT*2:

workaround

{
"scripts": {"report":"a(){ echo $2 $1; };a"}
}