[英]Mocking method with runnable arguments that return void
This is the interface of the method: 这是方法的接口:
void startWatch(MethodToWatch methodName, UUID uniqueID, Runnable toRun);
This is the implementation: 这是实现:
public void startWatch(MethodToWatch methodName, UUID uniqueID, Runnable toRun) {
this.startWatch(methodName, uniqueID);
start();
toRun.run();
stop();
}
i would like to mock this method with something like this: 我想用这样的东西来模拟这个方法:
IPerformanceStopWatch mock = mock(IPerformanceStopWatch.class);
when(performanceStopWatchFactory.getStartWatch()).thenReturn(mock);
when(mock.startWatch(any(), any(), any())).thenAnswer(new Answer<void>() {
@Override
public void answer(InvocationOnMock invocation) throws Throwable {
Object[] args = invocation.getArguments();
Runnable torun = (Callable)args[2];
torun.run();
return;
}
});
the problem is that when(...) cannot get a method with return value of void. 问题是when(...)无法获得返回值为void的方法。
how can i moke this method without using spy? 我如何不使用间谍就可以模仿这种方法?
Use doAnswer()
: 使用doAnswer()
:
// It is supposed here that Mockito.doAnswer is statically imported
doAnswer(...).when(mock).startWatch(etc);
You can just reuse the answer you have, which is good. 您可以重复使用已有的答案,这很好。
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