正确。越狱的转义序列？

Question

I am using a string as my source for an equation, and whenever I try to add something like an overbar tag which is: 我使用字符串作为方程式的来源，每当尝试添加类似overbar标记的东西时，它就是：

\ov5\ - creates a bar over the 5

However, when I add this into a Java string, for it to compile I am required to write it like this: 但是，当我将其添加到Java字符串中以进行编译时，我需要这样编写它：

string x= "\\ov5\\";

It would appear that this way breaks JQMath and doesn't work, resulting in a broken equation. 看来这种方式破坏了JQMath并且不起作用，从而导致方程破坏。 Here is the code in case I did something terribly wrong: 如果我做错了什么，下面是代码：

WebView webView;
String functext = "$$\\ov55\\$$";
    js = "<html><head>"
            + "<link rel='stylesheet' href='file:///android_asset/mathscribe/jqmath-0.4.3.css'>"
            + "<script src='file:///android_asset/mathscribe/jquery-1.4.3.min.js'></script>"
            + "<script src='file:///android_asset/mathscribe/jqmath-etc-0.4.3.min.js'></script>"
            + "</head><body>"
            + functext + "</body></html>";
    webView.loadDataWithBaseURL("", js, "text/html", "UTF-8", "");

EDIT: For clarification, the end result oddly reads "$$\\ov55$$". 编辑：为澄清起见，最终结果奇怪地显示为“ $$ \\ ov55 $$”。

Please note that when I try the same string on JQMath's website page here , it works as intended. 请注意，当我尝试JQMath的网站页面上相同的字符串在这里，它按预期工作。

EDIT2: Here are some debug values for a breakpoint placed at webView.loadDataWithBaseURL: EDIT2：以下是放置在webView.loadDataWithBaseURL上的断点的一些调试值：

actual string: String functext = "$$\\\\\\\\ov55\\\\\\\\$$"; 实际字符串：字符串functext =“ $$ \\\\\\\\ ov55 \\\\\\\\ $$”;

actual displayed result: $$\\ov55\\$$ 实际显示结果：$$ \\ ov55 \\ $$

debug results:
functext = $$\\ov55\\$$
js = <html><head><link rel='stylesheet' href='file:///android_asset/mathscribe/jqmath-0.4.3.css'><script src='file:///android_asset/mathscribe/jquery-1.4.3.min.js'></script><script src='file:///android_asset/mathscribe/jqmath-etc-0.4.3.min.js'></script></head><body>$$\\ov55\\$$</body></html>

Any help with loading it in another way other than a string would help greatly. 以字符串以外的其他方式加载它的任何帮助将大有帮助。

Answer 1

I think you want this: 我想你想要这个：

String functext = "$$\\ov55\\$$";

(The first \\ needs to be before the ov operator.) （第一个\\必须在 ov运算符之前。）

EDIT: Another possibility (since the above was evidently just a typo in your post, not in your code) is that somewhere in the pipeline the string is being interpolated a second time. 编辑：另一种可能性（因为以上内容显然只是您的帖子中的错字，而不是您的代码）是在管道中的某处第二次插入了字符串。 In that case, you would need to double-escape the backslashes: 在这种情况下，您需要对转义符进行两次转义：

String functext = "$$\\\\ov55\\\\$$";

PS If the end result reads "$$\\ov55$$" then the problem seems to be before jqmath sees anything. PS：如果最终结果为"$$\\ov55$$"则问题似乎出在jqmath看到任何东西之前。 The code you posted definitely does not produce that result for me. 你的代码贴绝对不会产生这一结果对我来说。

Answer 2

Also jqMath accepts ` (backquote) in place of \\ if that makes things easier. 如果jqMath使事情变得更容易，它也接受`（反引号）代替\\。 Finally, I'd put a space between the ov and the 5 to clarify that it's not a macro named ov5. 最后，我将在ov和5之间放置一个空格，以阐明它不是名为ov5的宏。 (Plus see my comment above to remove the final \\.) （此外，请参阅上面的我的评论以删除最终的\\。）

正确。越狱的转义序列？

问题描述

2 个解决方案

解决方案1
1 已采纳 2015-12-06 19:00:54

解决方案2
1 2015-12-07 19:13:56

正确。 越狱的转义序列？

问题描述

2 个解决方案

解决方案1 1 已采纳 2015-12-06 19:00:54

解决方案2 1 2015-12-07 19:13:56

正确。越狱的转义序列？

解决方案1
1 已采纳 2015-12-06 19:00:54

解决方案2
1 2015-12-07 19:13:56