JavaScript：提取字符串中所有出现的正则表达式

Question

I've got a Python function that makes a list of integer numbers out of a string containing clusters of digits:

def str_strip_numbers(s):
    """
    Returns a vector of integer numbers
    embedded in a string argument
    """
    return [int(x) for x in re.compile('\d+').findall(s)]

Given, say, an1kb12s336z , it returns [1,12,336]

What is the best way to get the same in JavaScript? I fiddled a bit with regular expressions, but did not gain much. This is not quite what I hoped for:

> var nn = /\d+/g
undefined
> nn
/\d+/g
> 'aba12gg4a'.search(nn)
3

Looks like I got the count of digits.

Answer 1

Search is not the function you are looking for. String.prototype.search() returns the position of the first matching result.

You should instead use String.prototype.match: 'aba12gg4a'.match(/\\d+/g) . This will return an array of all matches found in the source string.

Answer 2

you could try this. It will remove any letters from the string, and split to an array on the numbers. then filter out any values that don't parse with parseInt, meaning characters.

 'aba12gg4a'.split(/[^0-9]+/).reduce(function( ret, elem ){
        if (! isNaN(elem = parseInt(elem))){
            ret.push( elem );
        }
        return ret;
    }, []);

Answer 3

strStripNumbers: function(str) {
  return str.match(/\d+/g).map(__.parseInt);
}

__ means lodash library