正则表达式匹配带有五个正斜杠的字符串

Question

I want to write a regex to match any string with 5 forward slashes in. This is to match a URL in Google Analytics. I thought I had gotten close, but no cigar yet. This is what I've come up with:

\/.*\/.*\/.*\/.*\/.*$

But it doesn't match anything. How can I correct this? Or is it not possible?

Answer 1

The following regex will work :

.*(?:\/.*){5}

Explanation:

.*             # Any character (except newlines) 0 or more times
   (?:         # Start of non-capturing group
      \/       # Matches `/` literally (is esacped with a backslash)
        .*     # Any character (except newlines) 0 or more times
          )    # End of group
           {5} # The previous group five times

Answer 2

If you want just something like /aaa/bbb/ccc/ddd/, this will make the trick: /[^/]+/[^/]+/[^/]+/[^/]+/ However, there are more things to consider?

1. Is this the only format accepted?
2. Is it possible to have any chain of characters before the first slash?
3. Is it possible to have any chain of characters after the last slash?

If this one doesn't fit your needs, you as might as well provide some valid and invalid inputs.

Cheers.

Answer 3

您可以使用 "(\\w*\\W){5}"，因为 "\\W" 用于非单词字符。

Answer 4

Simple like this:

(/[^/]*){5}

Change * to + if you need at least a character between slashes.

Answer 5

I need to pull out links only have just string with excluding numbers and queries in URL in Google Analytics.

so, I need this URL

www.site.com/en/rent/cairo/apartments-for-rent/

and exclude these

www.website.com/en/buy/apartment-for-sale-in-acacia-compound-new-cairo-947145/

  www.website.com/en/buy/apartment-for-sale-in-acacia-compound-new-cairo-947145/?price=1000