[英]Calling a member constructor in class definition with a deleted copy constructor and initializer list overload
struct Foo
{
Foo(const Foo&) = delete;
Foo(int a, int b);
Foo(std::initializer_list<int>);
};
struct Bar
{
Foo f = Foo(1, 2);
// Foo f = {1, 2} - calls the initializer_list overload
};
How to initialize Foo with two ints if the copy constructor is deleted? 如果复制构造函数被删除,如何用两个整数初始化Foo?
In order for that initialization to work, the type in question has to be MoveConstructible * . 为了使该初始化起作用,所讨论的类型必须为MoveConstructible * 。 In your particular case, providing a move constructor would satisfy this requirement:
在您的特定情况下,提供一个move构造函数将满足此要求:
Foo(Foo&&) = default;
If this is not an option, you could initialize the member in a default constructor, and use it as a delegating constructor in other constructors. 如果这不是一个选项,则可以在默认构造函数中初始化该成员,并将其用作其他构造函数中的委派构造函数。
struct Bar
{
Bar() : f(1, 2) {}
Bar(const FooBar&) : Bar() {}
Bar(double x) : Bar() {}
Foo f;
};
* This does not mean a copy will be made. *这并不意味着将进行复制。
T t = T()
is an easy candidate for copy elision. T t = T()
是复制省略的简单候选。 However, a viable constructor must be accessible. 但是,必须有可行的构造函数。
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