我如何将此int转换为十进制格式

Question

Sorry if this is a noob question, but I can't recall ever having to do this before and the solution escapes me in C#. say I have two values;

int BeforeDecimal = 50000;
int AfterDecimal = 25;

How would I add these two int's to equal 50000.25m?

Adding int's wouldn't work, I need to be able to say to the int 25 to shift it's decimal places when adding it to BeforeDecimal. Also I cannot convert to a string since I need this to be a decimal. I suppose I could hack this to a string then convert to a decimal, but that just plain wrong.

Answer 1

If AfterDecimal will always be 2 places, you can divide by 100 and add them together.

If it won't, use

return (decimal)BeforeDecimal + ((decimal)AfterDecimal / (decimal)Math.Pow(10, Math.Ceiling(Math.Log10(AfterDecimal))));

Answer 2

Just divide AfterDecimal by 100 and sum to BeforeDecimal. The only thing to be aware is the Suffix m (for decimal) to let the language know that you want a floating point division and not an integer division.

decimal result = BeforeDecimal + (AfterDecimal / 100m);

Answer 3

decimal result = Convert.ToDecimal(BeforeDecimal) + (Convert.ToDecimal(AfterDecimal) / 100);

Answer 4

private decimal buttonOk_Click(int b, int a)
{
     return (decimal) b + ((decimal) a / 100.0));
}

Answer 5

Not the fastest solution, but how about:

decimal result = Decimal.Parse(String.Format("{0}.{1}", 
                 BeforeDecimal, AfterDecimal), CultureInfo.InvariantCulture);

You will avoid possible lose of precision of Pow , Ceil and division. In addition, it doesn't care how many digits you have after dot .