PHP从mssql提取数组中删除重复的值

Question

I have working php mssql query codes with array but output don't delete same chars. My codes here

    $querysfzzrf88 = " SELECT * FROM Style WHERE StyleNo='$StyleNo'";
        $resultsfzzrf88 = mssql_query($querysfzzrf88);


        //display the results 
        while($rowsfzzrf88 = mssql_fetch_array($resultsfzzrf88))
        {
        $Status88 = $rowsfzzrf88["Status"];


   echo $Status88;
}

Output

 LNNNMMMMMMM

Also

var_dump($Status88); 

Gives Like this

string(1) "N" string(1) "N" string(1) "N" string(1) "L"

I want Output

LNM

Answer 1

use count_chars()

$str = "LNNNMMMMMMM";

echo count_chars($str, 3); 

Second parameter is mode ,

3 - a string containing all unique characters is returned.

See demo here

Edit

Try this,

$str = " LNNNMMMMMMM";
echo preg_replace("/(.)\\1+/", "$1", $str); or echo preg_replace('/(.)\1+/', '$1', $str);

See demo here

Answer 2

sorry if I misunderstood your question, is this what you've expected:

<?php
$chars = 'LNNNMMMMMMM';
$array = str_split($chars);
$array = array_count_values($array);
$array = array_flip($array);
echo implode('', $array);
?>

it produces LNM as a result

UPDATE:

//display the results
$duplicated88 = $Status88 = $unique88 = array();
while($rowsfzzrf88 = mssql_fetch_array($resultsfzzrf88)){
    $duplicated88[] = $Status88[] = $unique88[] = $rowsfzzrf88["Status"];
}
sort($unique88); 
sort($duplicated88);
$unique88 = implode('', array_unique($unique88));

print($unique88);

Answer 3

USE DISTINCT in your mysql query to avoid duplicate values:

 $querysfzzrf88 = " SELECT DISTINCT status FROM Style WHERE StyleNo='$StyleNo'";
        $resultsfzzrf88 = mssql_query($querysfzzrf88);


        //display the results 
        while($rowsfzzrf88 = mssql_fetch_array($resultsfzzrf88))
        {
        $Status88 = $rowsfzzrf88["Status"];


   echo $Status88;
}