[英]how to use case with condition in mysql
using mysql query how to use case
with condition like ( manager_id=2
). 使用mysql查询如何使用条件为
case
( manager_id=2
)的情况。
i have three table with column 我有三个表列
user
- id
- name
- dept
- manager_id
itemone
- id
- detail
- status
- amount
- created_by
itemtwo
- id
- detail
- status
- amount
- created_by
based on status
column able to find draft, pending, approved and rejected . 根据
status
栏可以找到草稿,待审核,已批准和已拒绝 。
when my
manager_id
is2
then calculate total forpending
if not show as 0.00;当我的
manager_id
为2
,如果未显示为0.00,则计算pending
总数; How to write query for this?如何为此编写查询?
Sample Select Query: 样本选择查询:
SELECT t1.name, t1.dept, t1.manager_id, t2.draft_total, t2.pending_total, t2.approved_total, t2.rejected_total FROM user t1,
(
SELECT uat.created_by, SUM(uat.amount) AS total, SUM(uat.draft) AS draft_total, SUM(uat.pending) AS pending_total, SUM(uat.approved) AS approved_total, SUM(uat.rejected) AS rejected_total FROM
(
SELECT id, detail, status, amount, CASE status WHEN 1 THEN amount ELSE 0 END AS draft, CASE status WHEN 2 THEN amount ELSE 0 END AS pending, CASE status WHEN 3 THEN amount ELSE 0 END AS approved, CASE status WHEN 4 THEN amount ELSE 0 END AS rejected,created_by FROM itemone UNION ALL SELECT id, detail, status, amount, CASE status WHEN 1 THEN amount ELSE 0 END AS draft, CASE status WHEN 2 THEN amount ELSE 0 END AS pending, CASE status WHEN 3 THEN amount ELSE 0 END AS approved, CASE status WHEN 4 THEN amount ELSE 0 END AS rejected,created_by FROM itemtwo
)
uat GROUP BY uat.created_by
) t2 WHERE t1.id=t2.created_by ORDER BY name ASC;
Find Table Schema in SQLFiddle 在SQLFiddle中查找表架构
Getting Following Result 获得跟踪结果
name | dept | manager_id | draft_total | pending_total | approved_total | rejected_total
user four | Y | 2 | 79.75 | 54.10 | 90.30 | 100.20
user one | X | 1 | 79.75 | 54.10 | 90.30 | 100.20
user two | X | 1 | 84.25 | 0.00 | 0.00 | 0.00
Expecting Output: If Manager id is 2 then Result Should be 预期输出:如果Manager id为2,则结果应为
name | dept | manager_id | draft_total | pending_total | approved_total | rejected_total
user four | Y | 2 | 79.75 | 54.10 | 90.30 | 100.20
user one | X | 1 | 79.75 | 0.00 | 90.30 | 100.20
user two | X | 1 | 84.25 | 0.00 | 0.00 | 0.00
Try out this: 试试这个:
SELECT t1.name, t1.dept, t1.manager_id,
sum(case when t2.status=1 then t2.amount else 0 end) AS draft_total,
sum(case when t2.status=2 and t1.manager_id=2 then t2.amount else 0 end) AS pending_total,
sum(case when t2.status=2 then t2.amount else 0 end) AS approved_total,
sum(case when t2.status=4 then t2.amount else 0 end) AS rejected_total
FROM user t1
inner join (
select * from itemone
union all
select * from itemtwo
) t2 on t1.id=t2.created_by
group by t1.id
ORDER BY t1.name ASC
Try this one 试试这个
SELECT CASE user.manager_id WHEN 2 THEN SUM(pending) ELSE 0 END AS pending_total FROM ... WHERE ... SELECT CASE user.manager_id何时2 THEN SUM(pending)ELSE 0 END asending_total FROM ... WHERE ...
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