C ADT函数指针作为参数？

Question

I have a function in an ADT:

Pgroup new_group(int size, void (*foo)(void *));

In my other class I have this function to send in:

void foo(Pstruc x);

x is a pointer to a struct. When I try to call new_group however, I receive an error "expected 'void (*)(void )' but argument is of type 'void ( )(struct struc_ *)". This is how I've been calling it:

Pgroup group = new_group(num, &foo);

Any suggestions?

Answer 1

You can cast the argument to the correct type to get rid of the diagnostic:

Pgroup group = new_group(num, (void (*)(void *)) foo);

Note that this is not portable as C does not guarantee that the representation between different pointers is the same. The best would be to use types that match in their declarations.

Answer 2

You can rewrite your original function from void foo(Pstruc x); to void foo(void* x); .

Or convert its type: (void(*)(void*))foo .