在gulp-watch上运行可执行文件

Question

I want to run an executable or a "non-javascript script" on the event add using gulp-watch (so server/developer-side, not user-side). From searching around I'm guessing I need to use ajax as I want to avoid php, but this seems a bit roundabout. Is it possible to do this using node.js instead?

Answer 1

Supposing that you use it with gulp:

var gulp = require('gulp');
var watch = require('gulp-watch');
var filter = require('gulp-filter');
var exec = require('gulp-exec');

function isAdded(file) {
  return file.event === 'add';
}

var filterAdded = filter(isAdded);

gulp.task('default', function () {
  return gulp.src('**/*.js')
    .pipe(watch('**/*.js'))
    .pipe(filterAdded)
    .pipe(exec('ls -la'))
    .pipe(filterAdded.restore());
});