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简单的xml解析

[英]simple xml parsing

what is the simplest way to parse the lat and long out of the following xml fragment. 从以下xml片段中解析经纬度的最简单方法是什么? There is no namespace etc. 没有名称空间等。

It is in a string variable. 它在字符串变量中。 not a stream. 不是流。

<poi>
      <city>stockholm</city>
      <country>sweden</country>
      <gpoint>
        <lat>51.1</lat>
        <lng>67.98</lng>
      </gpoint>
</poi>

everything I have read so far is waaaaay too complex for what should be a simple task eg http://geekswithblogs.net/kobush/archive/2006/04/20/75717.aspx 到目前为止,我读过的所有内容对于一个简单的任务来说都是太复杂了,例如http://geekswithblogs.net/kobush/archive/2006/04/20/75717.aspx

I've been looking at the above link 我一直在看上面的链接

Surely there is a simpler way to do this in .net? 当然,.net中有一种更简单的方法吗?

Using Linq for XML: 使用Linq for XML:

   XDocument doc= XDocument.Parse("<poi><city>stockholm</city><country>sweden</country><gpoint><lat>51.1</lat><lng>67.98</lng></gpoint></poi>");

    var points=doc.Descendants("gpoint");

    foreach (XElement current in points)
    {
        Console.WriteLine(current.Element("lat").Value);
        Console.WriteLine(current.Element("lng").Value);
    }

    Console.ReadKey(); 
using System.IO;
using System.Xml;
using System.Xml.XPath;

. . .

    string xml = @"<poi>      
                     <city>stockholm</city>  
                     <country>sweden</countr>
                        <gpoint>        
                            <lat>51.1</lat>        
                            <lng>67.98</lng>    
                        </gpoint>
                   </poi>";

    XmlReaderSettings set = new XmlReaderSettings();
    set.ConformanceLevel = ConformanceLevel.Fragment;

    XPathDocument doc = 
        new XPathDocument(XmlReader.Create(new StringReader(xml), set));

    XPathNavigator nav = doc.CreateNavigator();


    Console.WriteLine(nav.SelectSingleNode("/poi/gpoint/lat"));
    Console.WriteLine(nav.SelectSingleNode("/poi/gpoint/lng"));

You could of course use xpath SelectSingleNode to select the <gpoint> element into a variable. 您当然可以使用xpath SelectSingleNode<gpoint>元素选择为变量。

Even simpler than Mitch Wheat's answer, since the fragment in question is a well-formed XML document: 甚至比Mitch Wheat的答案更简单,因为所讨论的片段是格式正确的XML文档:

using System.Xml;
using System.IO;

...

string xml = @"<poi>
                  <city>stockholm</city>
                  <country>sweden</country>
                  <gpoint>
                    <lat>51.1</lat>
                    <lng>67.98</lng>
                  </gpoint>
              </poi>";

XmlDocument d = new XmlDocument();
d.Load(new StringReader(xml));
Console.WriteLine(d.SelectSingleNode("/poi/gpoint/lat").InnerText);
Console.WriteLine(d.SelectSingleNode("/poi/gpoint/lng").InnerText);

If you can use LINQ for XML you can read those two values straight forward like this: 如果可以将LINQ用于XML,则可以像这样直接读取这两个值:

var doc = XDocument.Parse("...");
var point = doc.Element("poi").Element("gpoint");
Console.WriteLine("Lat: {0}, Lng: {1}",
    point.Element("lat").Value,
    point.Element("lng").Value);

If you need them as double you have to convert them: 如果您需要将它们加倍,则必须对其进行转换:

double lat = Convert.ToDouble(point.Element("lat").Value,
                 CultureInfo.InvariantCulture);

Don't forget to specify a culture that uses a dot for fractions. 不要忘记指定使用点表示分数的区域性。 Otherwise this would yield 511.0 as latitude. 否则,这将产生511.0的纬度。

Use XElement.Parse(string text) method to do this. 使用XElement.Parse(string text)方法执行此操作。

Example: 例:

string xmlString = @"<poi>
              <city>stockholm</city>
              <country>sweden</country>
              <gpoint>
                <lat>51.1</lat>
                <lng>67.98</lng>
              </gpoint>
          </poi>";
        try
        {
            XElement x = XElement.Parse(xmlString);
            var latLng = x.Element("gpoint");

            Console.WriteLine(latLng.Element("lat").Value);
            Console.WriteLine(latLng.Element("lng").Value);
        }
        catch
        {
        }

Hope this helps! 希望这可以帮助!

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