将unique_ptr的向量传递给函数，const引用

Question

I usually pass a vector containing raw pointers like this:

someFunc(const std::vector<MyClass*>& classList){..}

I wonder if you can do the same with unique_ptr like this:

 someFunc(const std::vector<std::unique_ptr<MyClass>>& classList){..}

? Does it mean the same thing?, ie read-only.

Answer 1

Yes, you can. No, it's doesn't mean the same thing: std::unique_ptr represents a resource that is owned by the pointer. A generic raw pointer can have many other semantics.

With regards to const correctness, accessing the elements of a vector with either iterators or operator[] will yield constant references to std::unique_ptr s. With a const std::unique_ptr<T> the pointer cannot be reassigned while the T object pointed to can be modified.