[英]MySQL update value +1 (increment) on button click
I know this question has been answered over a million times, but I'm very new to the whole programming scene and I just can't get it to work. 我知道这个问题已经被回答了一百万遍了,但是对于整个编程领域我还是很陌生,我无法使它正常工作。 Sorry, I hope you can help me!
对不起,希望您能帮帮我!
HTML: HTML:
<div class="the_score">+76</div>
<div id="increment_value">Like</div>
I have a MySQL connection and I can fetch the data, but I want the score to update with +1 when someone clicks the Like div. 我有一个MySQL连接,可以获取数据,但是当某人单击Like div时,我希望分数以+1更新。 I have a table "websites" with row "WebScore" that has the function int(10) (?? I hope that is correct).
我有一个表“ websites”,其中行“ WebScore”具有函数int(10)(??我希望这是正确的)。
I use this to fetch the data and show it on my website: 我用它来获取数据并将其显示在我的网站上:
$r = rand(2,3);
$sql = "SELECT * FROM websites WHERE ID = $r";
$result = $conn->query($sql);
$row = $result->fetch_assoc();
I presume you have a column , not a row , called WebScore. 我假设您有一列 ,而不是一行 ,称为WebScore。
You need the query 您需要查询
UPDATE websites SET WebScore = WebScore + 1 WHERE ID = $r
As you can see, it finds the right row of your table and updates the value of the WebScore column. 如您所见,它找到表的右行并更新WebScore列的值。
This sort of things can only be done from a PHP program. 这类事情只能通过PHP程序完成。 It can't be done directly from a Javascript method invoked within a web browser.
无法直接通过网络浏览器中调用的Javascript方法来完成。 So, if you want to react to a user click, you'll need to post a form or invoke an Ajax style call to a php endpoint.
因此,如果要对用户单击做出反应,则需要发布表单或对php端点调用Ajax样式调用。 How to do that is the province of another question.
如何做到这一点是另一个问题。
Keep plugging away; 保持堵塞; you'll figure out this database stuff.
您将弄清楚这个数据库的东西。
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