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XQuery删除元素-属性

[英]XQuery Remove Elements - Attributes

I have an XML from end system which require to remove all empty elements or attributes that have empty or null value. 我有一个来自最终系统的XML,它要求删除所有具有empty or nullempty or null值的空元素或属性。

Example

<Element>
    <fn att=""></fn>
    <fn att="1"></fn>
    <fn></fn>
    <fn att="">
      <child>1</child>
    </fn>
</Element>

This is my script given using XQuery to check and remove them 这是我使用XQuery检查并删除它们的脚本

declare function local:remove-empty-elements($nodes as node()*)  as node()* {
   for $node in $nodes
   return
     if ($node instance of element())
     then if (
       (normalize-space($node) = '') 
       and (not(normalize-space($node/@*)))   
     )
          then ()
          else element { node-name($node)
        }
       { $node/@*, local:remove-empty-elements($node/node())}
     else if ($node instance of document-node())
          then local:remove-empty-elements($node/node())
     else $node
};

This is successfully remove the elements and tag node that are single. 这样可以成功删除单个元素和标签节点。 But when i put multiple attributes in one element 但是当我将多个属性放在一个元素中时

eg <fn att1="Data" att2="1"></fn> 例如 <fn att1="Data" att2="1"></fn>

The function itself fails. 函数本身失败。

Any ideas how to achieve this? 任何想法如何实现这一目标?

Thank you before. 谢谢你

** UPDATE ** **更新**

As per har07 answer, if i want to change the function to remove the attribute that having empty value, is there any suggestions? 按照har07的答案,如果我想更改功能以删除具有空值的属性,有什么建议吗? I try with the logic if below but still sending the same result. 我尝试使用下面的逻辑,但仍然发送相同的结果。

declare function local:remove-empty-elements($nodes as node()*)  as node()* {
   for $node in $nodes
   return
     if ($node instance of element())
     then if (
       (normalize-space($node) = '') 
       and (not($node/@*[normalize-space(.)]))    
     )
          then (
            /* updated code here */
            if(($node/@*[normalize-space(.)])= '')  then ()
            else
              $node/@*[normalize-space(.)]

          )
          else element { node-name($node)
        }
       { $node/@*, local:remove-empty-elements($node/node())}
     else if ($node instance of document-node())
          then local:remove-empty-elements($node/node())
     else $node
};

This part was causing the problem : 这是造成问题的原因:

and (not(normalize-space($node/@*)))  

Call normalize-space() function in predicate for individual attribute instead of passing all attributes to the function at once, like so : 单个属性的谓词调用normalize-space()函数,而不是一次将所有属性传递给该函数,如下所示:

and (not($node/@*[normalize-space(.)]))  

update : 更新:

Regarding the question update, you can use the same predicate to filter the attributes so that you end up with non-empty attributes only. 关于问题更新,您可以使用相同的谓词来过滤属性,以便最终只获得非空属性。 In the inner else block, set content of the returned element as follow : 内部else块中,将返回元素的内容设置如下:

else element {node-name($node)}
             { 
                $node/@*[normalize-space(.)], 
                local:remove-empty-elements($node/node())
             }

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